A distribution of probabilities for random outcomes of bivariate or dichotomous random variables is called (A) binomial probability distribution.
<h3>
What is a binomial probability distribution?</h3>
- The binomial distribution with parameters n and p in probability theory and statistics is the discrete probability distribution of the number of successes in a succession of n separate experiments, each asking a yes-no question and each with its own Boolean-valued outcome: success or failure.
- The binomial distribution is widely used to describe the number of successes in a sample of size n selected from a population of size N with replacement.
- If the sampling is done without replacement, the draws are not independent, and the resulting distribution is hypergeometric rather than binomial.
- Binomial probability distribution refers to a distribution of probabilities for random outcomes of bivariate or dichotomous random variables.
As the description itself says, binomial probability distribution refers to a distribution of probabilities for random outcomes of bivariate or dichotomous random variables.
Therefore, a distribution of probabilities for random outcomes of bivariate or dichotomous random variables is called (A) binomial probability distribution.
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Complete question:
A distribution of probabilities for random outcomes of bivariate or dichotomous random variables is called a ______.
Group of answer choices
(A) binomial probability distribution
(B) distribution of expected values
(C) random variable distribution
(D) mathematical expectation
According to my calculations,
A. is the correct answer.
8√5
Answer:
The GCF is going to be 20
Step-by-step explanation:
This Is how I find the GCF of 2 numbers. I find the prime factorization first, then I find the common factors and multiply them. Here
The prime factorization of 20, 2 × 2 × 5= 20
The prime factorization of 80, 2 × 2 × 2 × 2 × 5 = 80
The common factors are 2, 2, and 5. We multiply those to get the GCF.
2 × 2 × 5 = 20
Answer:
lol but where is the main question
Using the z-distribution, it is found that the 95% confidence interval is (0.46, 0.526), and it does not provide strong evidence against that belief.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
We have that a random sample of 864 births in a state included 426 boys, hence the parameters are given by:

Then, the bounds of the interval are given by:


The 95% confidence interval estimate of the proportion of boys in all births is (0.46, 0.526). Since the interval contains 0.506, it does not provide strong evidence against that belief.
More can be learned about the z-distribution at brainly.com/question/25890103