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zepelin [54]
3 years ago
7

EXAMPLE 5 If F(x, y, z) = 4y2i + (8xy + 4e4z)j + 16ye4zk, find a function f such that ∇f = F. SOLUTION If there is such a functi

on f, then
Mathematics
1 answer:
Valentin [98]3 years ago
7 0

If there is such a scalar function <em>f</em>, then

\dfrac{\partial f}{\partial x}=4y^2

\dfrac{\partial f}{\partial y}=8xy+4e^{4z}

\dfrac{\partial f}{\partial z}=16ye^{4z}

Integrate both sides of the first equation with respect to <em>x</em> :

f(x,y,z)=4xy^2+g(y,z)

Differentiate both sides with respect to <em>y</em> :

\dfrac{\partial f}{\partial y}=8xy+4e^{4z}=8xy+\dfrac{\partial g}{\partial y}

\implies\dfrac{\partial g}{\partial y}=4e^{4z}

Integrate both sides with respect to <em>y</em> :

g(y,z)=4ye^{4z}+h(z)

Plug this into the equation above with <em>f</em> , then differentiate both sides with respect to <em>z</em> :

f(x,y,z)=4xy^2+4ye^{4z}+h(z)

\dfrac{\partial f}{\partial z}=16ye^{4z}=16ye^{4z}+\dfrac{\mathrm dh}{\mathrm dz}

\implies\dfrac{\mathrm dh}{\mathrm dz}=0

Integrate both sides with respect to <em>z</em> :

h(z)=C

So we end up with

\boxed{f(x,y,z)=4xy^2+4ye^{4z}+C}

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Answer:

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Step-by-step explanation:

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There is a circle with a center of 0,0 on a coordinate plane. There is one point on the circle's circumference in which the x:y
abruzzese [7]

Answer:

Step-by-step explanation:

Suppose the radius is 1. The parametric equations for the circle are

x = cosθ

y = sinθ

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cosθ = 3/√(1²+3²) =  3/√10

sinθ = 1/√10

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4 years ago
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Read 2 more answers
Which of the following equations have complex roots?
mestny [16]

Answer:

A

Step-by-step explanation:

Complex roots of quadratic functions occur when the <u>discriminant is negative</u>.

<u>Discriminant</u>

b^2-4ac\quad\textsf{when}\:\:ax^2+bx+c=0

Evaluate the discriminant of each of the given equations.

\textsf{A.} \quad 3x^2+2=0

\implies a=3, \quad b=0, \quad c=2

\implies b^2-4ac=0^2-4(3)(2)=-24

As -24 < 0 the equation will have complex roots.

\textsf{B.} \quad 2x^2+1=7x

\implies 2x^2-7x+1=0

\implies a=2, \quad b=-7, \quad c=1

\implies b^2-4ac= (-7)^2-4(2)(1)=41

As 41 > 0 the equation does not have complex roots.

\textsf{C.} \quad 3x^2-1=6x

\implies 3x^2-6x-1=0

\implies a=3, \quad b=-6, \quad c=-1

\implies b^2-4ac=(-6)^2-4(3)(-1)=48

As 48 > 0 the equation does not have complex roots.

\textsf{D.} \quad 2x^2-1=5x

\implies 2x^2-5x-1=0

\implies a=2, \quad b=-5, \quad c=-1

\implies b^2-4ac=(-5)^2-4(2)(-1)=33

As 33 > 0 the equation does not have complex roots.

Learn more about discriminants here:

brainly.com/question/27444516

brainly.com/question/27869538

Learn more about complex roots here:

brainly.com/question/26344541

6 0
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