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Rom4ik [11]
3 years ago
11

Mrs. Ameldo's class has 5 students with blue eyes, 7 with brown eyes, 4 with hazel eyes, and 4 with green eyes. Two students are

selected at random. Find each probability.
Probability of selecting a green eyed student, and then a brown eyed student =

P(two blue)
Mathematics
2 answers:
Advocard [28]3 years ago
5 0
Blue Eyes: 1/3
Brown Eyes: 7/15
Hazel Eyes: 4/15
Green Eyes: 4/15
sweet [91]3 years ago
4 0
<span>Probability of selecting a green eyed student: 4/(5+7+4+4)=4/20=1/5
</span><span> a brown eyed student: 7/20
That's your answers.</span>
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When a jar of fruit is 2/3 of the way full it can hold 2 1/4 cups of fruit what fraction of the jar is full when it only contain
Natali [406]

Answer:

8/27

Step-by-step explanation:

<h2><u>Fractions</u></h2>

a jar of fruit is 2/3 of the way full it can hold 2 1/4 cups of fruit

what fraction of the jar is full when it only contains one cup of fruit?

by using these statements , we can solve this through <u>cross multiplication</u>:

fraction that the jar is full                   :           number of cups of fruit

                 \frac{2}{3}                                         :                        2 \frac{1}{4}

                 x                                         :                        1

\frac{2}{3}  = 2 \frac{1}{4} x

convert 2 \frac{1}{4} from a mixed fraction to an improper fraction

hence 2 1/4  = 9/4

solve

\frac{2}{3}  = \frac{9}{4} x.

x = \frac{2}{3} /  \frac{9}{4}

<u>x = 8/27</u>

<h3><u>when the cup contains one cup of fruit its fraction 8/27 full </u></h3>
5 0
3 years ago
Read 2 more answers
PLEASE HELP!!
tensa zangetsu [6.8K]

Answer:C

Step-by-step explanation:There is definitely enough info.

And there are no angles so it has to be SSS~ (It's dilated by 1.5 by the way)

6 0
2 years ago
Read 2 more answers
My Notes A large manufacturing plant uses lightbulbs with lifetimes that are normally distributed with a mean of 1600 hours and
Evgen [1.6K]

Answer:

The bulbs should be replaced each 1436.9 hours.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1600, \sigma = 70

How often should the bulbs be replaced so that no more than 1% burn out between replacement periods?

This is the first percentile of hours. So it is X when Z has a pvalue of 0.01.

So it is X when Z = -2.33.

Z = \frac{X - \mu}{\sigma}

-2.33 = \frac{X - 1600}{70}

X - 1600 = -2.33*70

X = 1436.9

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6 0
3 years ago
Find the lateral area for the pyramid with the equilateral base
likoan [24]
<h3>The lateral area for the pyramid with the equilateral base is 144 square units</h3>

<em><u>Solution:</u></em>

The given pyramid has 3 lateral triangular side

The figure is attached below

Base of triangle = 12 unit

<em><u>Find the perpendicular</u></em>

By Pythagoras theorem

hypotenuse^2 = opposite^2 + adjacent^2

Therefore,

opposite^2 = 10^2 - 6^2\\\\opposite^2 = 100 - 36\\\\opposite^2 = 64\\\\opposite = 8

<em><u>Find the lateral surface area of 1 triangle</u></em>

\text{ Area of 1 lateral triangle } = \frac{1}{2} \times opposite \times base

\text{ Area of 1 lateral triangle } = \frac{1}{2} \times 8 \times 12\\\\\text{ Area of 1 lateral triangle } = 48

<em><u>Thus, lateral surface area of 3 triangle is:</u></em>

3 x 48 = 144

Thus lateral area for the pyramid with the equilateral base is 144 square units

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3 years ago
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Mamont248 [21]
Y=x-10/5 hope i help
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2 years ago
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