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fomenos
4 years ago
10

Write a function that converts x days to y hours.

Mathematics
1 answer:
valina [46]4 years ago
8 0
Y = 24x
this is because there are 24 hours in a day, so multiplying the number of days (x) by 24 would give you the number of hours (y)
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The cafeteria offers four types of eggs, two
-BARSIC- [3]
2 x 4 x 3 = 24
There are 24 different possible combinations.
5 0
3 years ago
What aspect of a line of a linear equation does the slope affect? What does the y-intercept affect?
alekssr [168]

Answer: The y-intercept affects where the linear equation meet the y-axis. The slope affects how steep the linear equation is on the graph.

4 0
3 years ago
There are black, blue, and white marbles in a bag. The probability of choosing a black marble is 0.36. The probability of choosi
Gala2k [10]

Answer: c) 0.75

Step-by-step explanation:

Given : The probability of choosing a black marble is P(Black)= 0.36.

The probability of choosing a black and then a white marble is P( Black and white) = 0.27.

Then by conditional probability ,

The probability of the second marble being white if the first marble chosen is black = P(\text{white }|\text{Black})=\dfrac{\text{P( Black and white)}}{\text{P(Black}}

=\dfrac{0.27}{0.36}=\dfrac{27}{36}=0.75

Therefore , the probability of the second marble being white if the first marble chosen is black = 0.75

8 0
3 years ago
find the measure of an angle between 0 and 360 coterminal coterminal with the given angle 495 degrees
ikadub [295]

Answer:

135 degrees

Step-by-step explanation:

Coterminal means it ends at the same spot around the circle.

To calculate the resulting angle we need to reduce/increase the started value to arrive to a value between 0 and 359 degrees.  

If the starting angle is greater or equal to 360, we subtract 360 until we get below 360.

If the starting angle is below 0, we add 360 until we get equal or greater than 0.

So, starting with 495, we subtract 360 a first time....

A = 495 - 360 = 135

We're already in the desired range (0-359)... so we have our answer.

4 0
3 years ago
The following data are from an experiment designed to investigate the perception of corporate ethical values among individuals w
alukav5142 [94]

Answer:

Part 1

a. Sum of Squares, Treatment= 61

b. Sum of Squares, Error= 7.5

c. Mean Squares, Treatment = 30.5

d. Mean Squares, Error= 0.5

2. the F value lies in the rejection region > 3.6823

3. The value of the test statistic = 61

4. The p-value is < 0.00001

5. Conclusion

Since p-value < α, H0 is rejected.

6. Between x`2 and x`3

7. Fisher's Least Significant Difference value almost 0.869

8.There is a significant difference between the means

Step-by-step explanation:

Summary of Data

                       <u>   Treatments</u>

                       1             2             3                 Total

n                      6             6             6                   18

∑x                   42          57           30                  129

Mean              7            9.5           5                  7.167

<u>∑x2              298         543        152                    993</u>

<u>Sd.D       0.8944     0.5477     0.6325           2.0073</u>

ANOVA Table

<u>Source                                  SS              df                  MS </u>

Between-treatments           61              2                   30.5       F = 61

<u>Error                                     7.5           15                     0.5 </u>

<u>Total                                     6             8.5                     17 </u>

a. Sum of Squares, Treatment= 61

b. Sum of Squares, Error= 7.5

c. Mean Squares, Treatment = 30.5

d. Mean Squares, Error= 0.5

2. Using alpha= 0.05 the F value lies in the rejection region i.e F > 3.6823

x1` -x2`= 7-9.5= -2.5 Not significant as difference <3.68

x1`- x3`= 7-5= 2 Not significant as difference <3.68

x2` -x3`= 9.5-5= 4.5 Significant as difference > 3.68

3. The value of the F test statistic = 61

4. The p-value is < 0.00001

5. Conclusion

<em>Since p-value < α, H0 is rejected.</em>

6. Using alpha= .05, differences occurs between x2` and x3` as their difference is greater than 3.68

7. Fisher's Least Significant Difference value almost 0.869

Least Significant Difference= t( 0.025,15) √2s²/r s²= 0.50 r= 6 =n1=n2=n3

Least Significant Difference= 2.13 √ 2*0.50/ 6

=0.869

8.There is a significant difference between the means

x1` -x2`= 7-9.5= -2.5 Significant as difference > Least Significant Difference

x1`- x3`= 7-5= 2 Significant as difference > Least Significant Difference

x2` -x3`= 9.5-5= 4.5 Significant as difference > Least Significant Difference

6 0
3 years ago
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