A train leaves the station at time xequals
0.
Traveling at a constant speed, the train travels 328
km in 3.4
h. Round to the nearest 10 km and the nearest whole hour. Then represent the distance, y, the train travels in x hours using a table, an equation, and a graph. give brainliest x
Answer:
8n^2 8n squared
Step-by-step explanation:
It is not bigger. 25.879 is bigger by .100
<u>Finding x:</u>
We know that the diagonals of a rhombus bisect its angles
So, since US is a diagonal of the given rhombus:
∠RUS = ∠TUS
10x - 23 = 3x + 19 [replacing the given values of the angles]
7x - 23 = 19 [subtracting 3x from both sides]
7x = 42 [adding 23 on both sides]
x = 6 [dividing both sides by 7]
<u>Finding ∠RUT:</u>
We can see that:
∠RUT = ∠RUS + ∠TUS
<em>Since we are given the values of ∠RUS and ∠TUS:</em>
∠RUT = (10x - 23) + (3x + 19)
∠RUT = 13x - 4
<em>We know that x = 6:</em>
∠RUT = 13(6)- 4
∠RUT = 74°
Answer: 7/3
Step-by-step explanation:
R-P= (3,-7). the displacement vector.
P+x(R-P) moves to x times distance between
P+(R-P) = R moves to 100% of the distance.
Q = P+2/3(R-P)
= (-2,7)+2/3(3,-7)
= (-2,7)+(2,-14/3)
= (0,7-14/3)
= (0,7/3)
= (0,2.3333...)
