Explain how the diagram can help find the area of a circle
1 answer:
Answer:
Step-by-step explanation:
This is a really famous diagram! The circle has been divided into many wedges (think slices of pizza!). The wedges have been colored alternately blue and yellow, then the wedges were rearranged to form a "rectangle" -- well, it's approximately a rectangle because the wedges have arcs (pieces of a circle) on them. See how the bottom and top edges of the rectangle look bumpy?
The area of the "rectangle" is approximately . The reason is that the height of the rectangle is <em>r</em> , the radius of the circle. And the length of the rectangle is about
-- half the circumference of the circle. It's half because the circumference is in the bumpy parts of the wedges--half blue, half yellow.
The approximation improves as the number of wedges increases. In fact, as the number of slices (sorry, pizza again) gets larger, the length of the rectangle gets closer and closer to half the circumference. In other words, making more wedges makes the rectangle less bumpy!
You might be interested in
Answer:
15 goals out of 50 penalty kicks was scored by brock
Step-by-step explanation:
If Brock shoots 50 penalty kicks and the probability that he scores a penalty kick is 3/10, the number of goal brock is expected to make can be expressed as:
Number of goals scored = probability value * total penalty kicks taken
Number of goals scored =
Number of goals scored =
El cable experimenta un esfuerzo axial de 79577.472 pascales por el peso de la caja.
<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>
La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.
Asumiendo una distribución uniforme de la fuerza sobre toda la superficie transversal de la cuerda, tenemos que el esfuerzo axial se calcula mediante la siguiente expresión:
σ = W / (π · D² / 4)
Donde:
- W - Peso de la caja, en newtons.
- D - Diámetro del área transversal de la caja, en metros.
Si sabemos que W = 25 N y D = 0.02 m, entonces el esfuerzo axial aplicado a la cuerda es:
σ = 25 N / [π · (0.02 m)² / 4]
σ ≈ 79577.472 Pa
<h3>Observación</h3>La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.
Para aprender más sobre esfuerzos axiales: brainly.com/question/13683145
#SPJ1
