Given the domain {-4, 0, 5}, what is the range for the relation 12x 6y = 24? a. {2, 4, 9} b. {-4, 4, 14} c. {12, 4, -6} d. {-12,
xz_007 [3.2K]
The domain of the function 12x + 6y = 24 exists {-4, 0, 5}, then the range of the function exists {12, 4, -6}.
<h3>How to determine the range of a function?</h3>
Given: 12x + 6y = 24
Here x stands for the input and y stands for the output
Replacing y with f(x)
12x + 6f(x) = 24
6f(x) = 24 - 12x
f(x) = (24 - 12x)/6
Domain = {-4, 0, 5}
Put the elements of the domain, one by one, to estimate the range
f(-4) = (24 - 12((-4))/6
= (72)/6 = 12
f(0) = (24 - 12(0)/6
= (24)/6 = 4
f(5) = (24 - 12(5)/6
= (-36)/6 = -6
The range exists {12, 4, -6}
Therefore, the correct answer is option c. {12, 4, -6}.
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Sam paid $ 124.032 as tax deduction each week.
<h3>What is an Equation ?</h3>
An equation is a mathematical statement formed when an algebraic expression is equated by an equal sign by a constant or algebraic expression.
It is given that
weekly earnings of Sam is $912
Tax deduction is 13.6 %
Let the amount of Tax deduction is represented by $x
Then the equation formed is
x = 13.6 % 912
x = 13.6 *912 /100
x = $ 124.032
Therefore Sam paid $ 124.032 as tax deduction each week.
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A and D
should be the answers.
Answer: 11 people
Explanation:
Find the total people who actually drink something:
120 - 17 = 103
Find the sum of people who drink cold and soft drink:
88 + 26 = 114
Find the people who drinks both:
114 - 103 = 11 people
Answer: x = 0 y = –3
Step-by-step explanation:
We can solve this system by substitution.
use the second equation as a value for x.
Then substitute that value in place of x in the first equation and solve for y.
6x - 5y = 15 becomes
6(y + 3) - 5y = 15 Distribute 6 × parentheses
6y + 18 - 5y = 15 combine like terms
6y -5y + 18 = 15
y + 18 = 15 Subtract 18 from both sides.
y =15 -18
y = –3
Use this value for y in either equation to solve for x
6x - 5(-3) = 15
6x + 15 = 15 Subtract 15 from both sides, divide by 6 (seems silly!)
x = 0
OR in he second equation,
x = -3 + 3
Again, x = 0
