Answer:
a) E(x)=3.565
b) c=3.8475 --> P(X < 3.8475) = 0.75
c) The probability that X falls above or below 0.28 min from the mean is P=0.4954.
Step-by-step explanation:
We have the cumulative distribution function as information.
a) To calculate the expected value, we can calculate the value of x in which F(x) equals 0.5. This happens for x=3.565.
b) What is the value c such that P(X < c) = 0.75?
In this case, we have to calculate x to have F(x)=0.75
This happens for x=3.8475.
c) We have to calculate the probability that X falls above or below 0.28 min from the mean (x=3.565).
This is the probability that the time is between 3.285 and 3.845
We can calculate this as:
The probability that X falls above or below 0.28 min from the mean is P=0.4954.
F(x)=7-3x g(x)=3x-7
First let’s solve for f(1)
f(1)= 7-3(1)
f(1)= 7-3
f(1)= 4 *we will save this for later
Let’s now solve for g(1)
g(1)= 3(1)-7
g(1)= 3-7
g(1)= -4
Now we can find f(1) + g(1)
f(1) =4 and g(1)= -4
4+(-4) = 0
So first we establish that opposite angles are equal, and therefore 12x-28 is equal to 5x+38
Then we establish that opposition sides are equal, and therefore 3y+3 is equal to 24
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Answer:
it could be the 5th one !!