6E and 7 with full explanation
2 answers:
Answer:
See below ~
Step-by-step explanation:
Question 6(e) :
⇒ x² ≤ 16
<em>Take square root on each side :</em>
⇒ √x² ≤ √16
⇒ x ≤ 4 and x ≥ -4
⇒ -4 ≤ x ≤ 4
<h3><u>Part 6e</u></h3>
⇒ x² ≤ 16
Apply the <u>absolute rule</u> if x² < a then -√a < x < √a
⇒ -√16 ≤ x ≤ +√16
⇒ -4 ≤ x ≤ 4
<h3><u>Part 7</u></h3>
First of all, The student should have <u>subtracted both sides by 4</u>
What he should have done:







⇒ -4x + 11 = 0, x - 2 = 0
⇒ -4x = -11, x = 2
⇒ x = 11/4 , x = 2
Solution <u>satisfying the inequality</u>:
⇒ 2 < x < 11/4
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