percent error=100 times error/predicted
error=175-100=75
predicted=100
percent error=100 times 75/100=75
the answer si 75% error
The student that simplified the expression incorrectly is student 2
<h3>How to determine the incorrect result?</h3>
The steps are given as:
Student 1:
- Step 1:
- Step 2:
- Step 3: 1 + tan²(Ф)
- Step 4: sec²(Ф)
Student 2:
- Step 1:
- Step 2:
- Step 3: sec²(Ф)/tan²(Ф)
- Step 4: csc²(Ф)
As a general trigonometry rule;
This means that student 1 is correct, while student 2 is not
The first error in student 2's workings is in step 2, where we have:
The above expression is not justified and cannot be proved by any trigonometry rule
Since the step 2 is incorrect, the other steps cannot be used.
Hence, the student that simplified the expression incorrectly is student 2
Read more about trigonometric expressions at:
brainly.com/question/8120556
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You can do this by multiplying 10000 by 103.4 percent
10,000 times 100 percent is 10,000 so 10,000 times 103.4 percent is the extra 3.4 percent
You would have earned 340 dollars in a years time
Call the notebooks x, and the pencils y.
<span>3x + 4y = $8.50 and 5x + 8y = $14.50 </span>
<span>Then just solve as simultaneous equations: </span>
<span>3x + 4y = $8.50 </span>
<span>5x + 8y = $14.50 </span>
<span>5(3x + 4y = 8.5) </span>
<span>3(5x + 8y = 14.5) </span>
<span>15x + 20y = 42.5 </span>
<span>15x + 24y = 43.5 </span>
<span>Think: DASS (Different Add, Similar Subtract). 15x appears in both equations so subtract one equation from the other. Eassier to subtract (15x + 20y = 42.5) from (15x + 24y = 43.5) </span>
<span>(15x + 24y = 43.5) - (15x + 20y = 42.5) = (4y = 1) which means y = 0.25. </span>
<span>Then substitue into equation : </span>
<span>15x + 20y = 42.5 </span>
<span>15x + 5 + 42.5 </span>
<span>15x = 42.5 - 5 = 37.5 </span>
<span>15x = 37.5 </span>
<span>x = 2.5 </span>
<span>15x + 24y = 43.5 </span>
<span>15(2.5) + 24(0.25) </span>
<span>37.5 + 6 = 43.5 </span>
<span>So x (notebooks) are 2.5 ($2.50) each and y (pencils) are 0.25 ($0.25) each.</span>
