earthworms he can have if his square of compost has a side length that is 3 times longer .
<u>Step-by-step explanation:</u>
Here we have , Hiram raises earthworms. in a square of compost 4ft by 4ft he can have 1000 earthworms. We need to find how many earthworms can he have if his square of compost has a side length that is 3 times longer .
Area of square compost =
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In this , square compost with can have 1000 earthworms ! if side is 3 times longer i.e. New side = , So , new area will be :
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Now , can have 1000 earthworms ,So will have :
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Therefore, earthworms he can have if his square of compost has a side length that is 3 times longer .
Answer:
200(1.10) to the 20 power.=$1345.499 rounded to nearest 10th is $1345.4
Step-by-step explanation: you start with $200 times 1.10 which represents one 10%. you will then set up the formula to the 20th power to shorten your steps which represents the 20 weeks the 10 % would be added. and your answer would be $1345.4 if you rounded it to the nearest 10th.
Answer:
s = 53
Step-by-step explanation:
We know that the three angle measures in a triangle add up to 180°. so…
(s - 20°) + 2s + 41° = 180°
Step 1. Subtract 41 from both sides
(s - 20°) + 2s = 139°
Step 2. Combine like terms
3s - 20 = 139°
Step 3. Add 20 from both sides
3s = 159
Step 4. Solve for s
s = 159/3
s = 53
Step-by-step explanation:
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Answer:
Step-by-step explanation:
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