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Iteru [2.4K]
3 years ago
10

need help plz....What is a bug? A. A person who tests a program B. An error in a program's code C. A window that runs a program

D. A comment in a program
Computers and Technology
2 answers:
Ludmilka [50]3 years ago
6 0
B) a error in a programs code
hope this helps!

btw make me brainliest?
serious [3.7K]3 years ago
5 0

In programming, a bug would be (B.) an error in a program's code.

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Given the following function definition:
neonofarm [45]

The question is incomplete! Complete question along with its step by step answer is provided below!

Question:

Given the following function definition:

void calc (int a, int& b)

{

int c;

c = a + 2;

a = a * 3;

b = c + a;

}

x = 1;

y = 2;

z = 3;

calc(x, y);

cout << x << " " << y << " " << z << endl;

What is the output of the following code fragment that invokes calc?

a. 1 2 3

b. 1 6 3

c. 3 6 3

d. 1 14 9

e. None of these

Answer:

b. 1 6 3

Explanation:

In the given problem we have a function void calc which takes two input arguments a and b and updates its values according to following equations

c = a + 2;

a = a * 3;

b = c + a;

Then we call this function calc(x,y) by providing test values of

int x = 1;

int y = 2;

int z = 3;

and the output returns the values of x, y and z

cout << x << " " << y << " " << z << endl;

Lets find out what is happening here!

When the program runs we provide x=a=1 and y=b=2

c=a+2=1+2=3

a=a*3=1*3=3

b=c+a=3+3=6

So the updated values of a=x=3 and b=y=6?

NO!

The updated values are a=x=1 and b=y=6

WHY?

There are two ways to pass values

1. Pass by values -> value cannot change  (int a)

2. Pass by reference -> value can change (int& b)

Look at the function void calc (int a, int& b) ;

Here we are passing (int a) as a value and (int& b) as a reference, therefore x remains same x=1 and y gets changed to updated value y=6 and z remains same as z=3 since it wasnt used by function calc(x,y)

The right answer is:

b. 1 6 3

x=1, y=6, z=3

4 0
3 years ago
Design a class that has an array of floating-point numbers. The constructor should accept an integer argument and dynamically al
attashe74 [19]

Answer:

See explaination for the code

Explanation:

Here is the code

class NumberArray

{

private:

float *aptr; // Pointer to the array

int arraySize; // Holds the array size

float max,min,avg;

public:

NumberArray(int); // Constructor

~NumberArray(); // Destructor

int size() const // Returns the array size

{ return arraySize; }

void storeNumber(float num,int ele);

float retrieveNumber(int ele);

float getHighest();

float getLowest();

float getAverage();

};

//*******************************************************

// Constructor for IntArray class. Sets the size of the *

// array and allocates memory for it. *

//*******************************************************

NumberArray::NumberArray(int s)

{

arraySize = s;

aptr = new float [s];

for (int count = 0; count < arraySize; count++)

*(aptr + count) = 0;

}

//******************************************************

// Destructor for IntArray class. *

//******************************************************

NumberArray::~NumberArray()

{

if (arraySize > 0)

delete [] aptr;

}

void NumberArray::storeNumber(float num,int ele)

{

if(ele<arraySize)

*(aptr+ele)=num;

}

float NumberArray::retrieveNumber(int ele)

{

return *(aptr+ele);

}

float NumberArray::getHighest()

{

float high=*(aptr+0);

for(int i=1;i<arraySize;i++)

if(high<*(aptr+i))

high=*(aptr+i);

return high;

}

float NumberArray::getLowest()

{

float low=*(aptr+0);

for(int i=1;i<arraySize;i++)

if(low>*(aptr+i))

low=*(aptr+i);

return low;

}

float NumberArray:: getAverage()

{

float ag=0;

for(int i=1;i<arraySize;i++)

ag+=*(aptr+i);

ag=ag/arraySize;

return ag;

}

//Header file section

#include <iostream>

using namespace std;

int main()

{

const int SIZE = 10; // Array size

// Define an IntArray with 10 elements.

NumberArray table(SIZE);

//function call to store values

table.storeNumber(1,0);

table.storeNumber(3,1);

table.storeNumber(7,2);

table.storeNumber(2,3);

//display values

cout<<"Highest value:"<<table.getHighest()<<endl;

cout<<"Lowest Value:"<<table.getLowest()<<endl;

cout<<"Average:"<<table.getAverage()<<endl;

///pause system for a while

system("pause");

return 0;

}

6 0
3 years ago
Why do astronomers prefer to use the reflecting telescope rather than the refracting telescope to view distant objects in space?
sdas [7]
C is the right answer
7 0
3 years ago
Read 2 more answers
Subcribe to me for brainly my YT is KeepUsweatin
Flura [38]

Answer:

Ok got you. Will do so. Mine is Phantom Pac.

5 0
3 years ago
How to convert 23.125 to binary (Hex) using the double - precision representation
Svet_ta [14]

Answer:-

(10111.001)₂

Explanation:

To convert a decimal number to a binary number we have to constantly divide the decimal number by 2 till the decimal number becomes zero and the binary number is writing the remainders in reverse order of obtaining them on each division.

Hence the binary number is 10111.001

To convert binary to hexa decimal we to make a group 4 binary bits starting from the decimal and moving outwards if the last group is not of 4 then add respective 0's and write the corresponding hexa decimal number.

<u>0001</u>  <u>0111</u> . <u>0010</u>

   1        7         2

Hence the hexadecimal number is 17.2

6 0
3 years ago
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