Hurry please

Hot components or sharp edges of computer is an example of what hazard

Alexxandr [17]

Answer:

hot components or sharp edges of computer is an example of a mechanical hazard

6 0

3 years ago

2. Sometimes, validating the HTML code for a web page will help you debug an application, because a. the page won’t run in a bro

aleksandrvk [35]

Answer:

Option c. you can be sure that a validated page will work correctly in a browser

Explanation:

A faulty HTML codes can result in various types of unexpected error when running the web page in different platforms or browsers. This will cause an inconsistent style or layout. HTML code validation can check if the code adopt the standard tag and structure. A validated HTML code can guarantee a web application running smoothly in different browsers and always present consistent web page layout to users. HTML code validation has become part of the standard workflow before a web page go live in internet.

4 0

3 years ago

Write a recursive function that takes a non-negative integer as an argument and displays the same number in reverse order (i.e.

avanturin [10]

Answer:

Following are the program in C++ language

#include<iostream> // header file

using namespace std; // namespace std

int reverse(int n1); // function prototype

int main() // main function()

{

int num; // Variable declaration

cout << "Enter the number" << endl;

cin >> num; // Read the number bu the user

cout<<"After Reverse the digit:\n";

int res= reverse(num); // calling function reverse

cout<<res; // display

}

int reverse(int n1) // function definition of reverse

{

if (n1<10) // checking the base condition

{

return n1;

}

else

{

cout << n1 % 10; // Printed the last digit

return reverse(n1/10); // calling itsself

}

Output:

Enter the number:

76538

After Reverse the digit:

83567

Explanation:

Following are the description of the program

In the main function read the number by user in the "num" variable of int type.

Calling the reverse and pass that "num" variable into it.

After calling the control moves to the body of the reverse function.In this function we check the two condition

1 base condition

if (n1<10) // checking the base condition

{

return n1;

}

2 General condition

else

{

cout << n1 % 10; // Printed the last digit

return reverse(n1/10); // calling itsself

}

Finally return the reverse number and display them into the main function.

5 0

3 years ago

The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices

erma4kov [3.2K]

Answer:

In Java:

import java.util.Scanner;

import java.util.Arrays;

public class Main {

public static void main(String args[]) {

Scanner input = new Scanner(System.in);

int row, col;

System.out.print("Rows: "); row = input.nextInt();

System.out.print("Cols: "); col = input.nextInt();

int[][] Array2D = new int[row][col];

System.out.print("Enter array elements: ");

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

Array2D[i][j] = input.nextInt();

} }

int[] maxarray = findmax(Array2D,row,col);

System.out.println("Row: "+(maxarray[0]+1));

System.out.println("Column: "+(maxarray[1]+1));

}

public static int[] findmax(int[][] Array2D,int row, int col) {

int max = Array2D[0][0];

int []maxitem = new int [2];

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

if(Array2D[i][j] > max){

maxitem[0] = i;

maxitem[1] = j; } } }

return maxitem;

}

Explanation:

The next two lines import the scanner and array libraries

import java.util.Scanner;

import java.util.Arrays;

The class of the program

public class Main {

The main method begins here

public static void main(String args[]) {

The scanner function is called in the program

Scanner input = new Scanner(System.in);

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input

System.out.print("Rows: "); row = input.nextInt();

This next instructions prompt the user for columns and get the column input

System.out.print("Cols: "); col = input.nextInt();

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

Array2D[i][j] = input.nextInt();

} }

This calls the findmax function. The returned array of the function is saved in maxarray

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col) {

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

for(int i =0;i<row;i++){

for(int j =0;j<col;j++){

if(Array2D[i][j] > max){

maxitem[0] = i; -- The row position is saved in index 0

maxitem[1] = j; -- The column position is saved in index 1} } }

This returns the 1 d array

return maxitem;

}

7 0

3 years ago

How to recover permanently deleted files from drive

HACTEHA [7]

Go into your trash bin in your computer.

7 0

3 years ago