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Inga [223]
3 years ago
12

Hurry please

Computers and Technology
1 answer:
Yanka [14]3 years ago
3 0

Answer:

to get the client to imagine

Explanation:

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Hot components or sharp edges of computer is an example of what hazard​
Alexxandr [17]

Answer:

hot components or sharp edges of computer is an example of a mechanical hazard

6 0
3 years ago
2. Sometimes, validating the HTML code for a web page will help you debug an application, because a. the page won’t run in a bro
aleksandrvk [35]

Answer:

Option c. you can be sure that a validated page will work correctly in a browser

Explanation:

A faulty HTML codes can result in various types of unexpected error when running the web page in different platforms or browsers. This will cause an inconsistent style or layout. HTML code validation can check if the code adopt the standard tag and structure. A validated HTML code can guarantee a web application running smoothly in different browsers and always present consistent web page layout to users. HTML code validation has become part of the standard workflow before a web page go live in internet.

4 0
3 years ago
Write a recursive function that takes a non-negative integer as an argument and displays the same number in reverse order (i.e.
avanturin [10]

Answer:

Following are the program in C++ language

#include<iostream> // header file

using namespace std; // namespace std

int reverse(int n1); // function prototype

int main()  // main function()

{

   int num; // Variable declaration

   cout << "Enter the number" << endl;

   cin >> num; // Read the number bu the user

  cout<<"After Reverse the digit:\n";

   int res= reverse(num); // calling function reverse

   

   cout<<res; // display  

}

int reverse(int n1) // function definition of reverse

{

   if (n1<10)  // checking the base condition

       {

           return n1;

       }

   else

       {

           cout << n1 % 10; // Printed the last digit

          return reverse(n1/10); // calling itsself

}

}

Output:

Enter the number:

76538

After Reverse the digit:

83567

Explanation:

Following are the description of the program

  • In the main function read the number by user in the "num" variable of int type.
  • Calling the reverse and pass that "num" variable into it.
  • After calling the control moves to the body of the reverse function.In this function we check the two condition

        1  base condition

   if (n1<10)  // checking the base condition

       {

           return n1;

     }

      2  General condition

  else

       {

           cout << n1 % 10; // Printed the last digit

          return reverse(n1/10); // calling itsself

       }

  • Finally return the reverse number and display them into the main function.
5 0
3 years ago
The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices
erma4kov [3.2K]

Answer:

In Java:

import java.util.Scanner;  

import java.util.Arrays;  

public class Main  {  

public static void main(String args[])  {  

Scanner input = new Scanner(System.in);

int row, col;  

System.out.print("Rows: ");    row = input.nextInt();

System.out.print("Cols: ");     col = input.nextInt();  

int[][] Array2D = new int[row][col];

System.out.print("Enter array elements: ");

for(int i =0;i<row;i++){    

    for(int j =0;j<col;j++){

        Array2D[i][j] = input.nextInt();  

    }     }

 

int[] maxarray = findmax(Array2D,row,col);

System.out.println("Row: "+(maxarray[0]+1));

System.out.println("Column: "+(maxarray[1]+1));

}  

public static int[] findmax(int[][] Array2D,int row, int col)   {  

int max = Array2D[0][0];

int []maxitem = new int [2];

for(int i =0;i<row;i++){

    for(int j =0;j<col;j++){

        if(Array2D[i][j] > max){  

            maxitem[0] = i;

            maxitem[1] = j; } }    }

 

return maxitem;  

}  

}

Explanation:

The next two lines import the scanner and array libraries

<em>import java.util.Scanner;   </em>

<em>import java.util.Arrays;   </em>

The class of the program

<em>public class Main  {  </em>

The main method begins here

<em>public static void main(String args[])  {  </em>

The scanner function is called in the program

<em>Scanner input = new Scanner(System.in);</em>

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input  

System.out.print("Rows: ");    row = input.nextInt();

This next instructions prompt the user for columns and get the column input  

System.out.print("Cols: ");     col = input.nextInt();  

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

<em> for(int i =0;i<row;i++){    </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         Array2D[i][j] = input.nextInt();   </em>

<em>     }     } </em>

This calls the findmax function. The returned array of the function is saved in maxarray  

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}  

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col)   {  

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

<em>for(int i =0;i<row;i++){ </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         if(Array2D[i][j] > max){  </em>

<em>             maxitem[0] = i; </em><em>-- The row position is saved in index 0</em><em> </em>

<em>             maxitem[1] = j;  </em><em>-- The column position is saved in index 1</em><em>} }    } </em>

This returns the 1 d array

return maxitem;  

}  

7 0
3 years ago
How to recover permanently deleted files from drive
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Go into your trash bin in your computer.
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