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lbvjy [14]
3 years ago
13

Find the area of the parallelogram.

Mathematics
2 answers:
frozen [14]3 years ago
8 0

Answer:216 cm

Step-by-step explanation:

Step 1:Find the base and height base:18 cm height:12 cm.

Step 2:Multiply the base and height 18 cm*12 cm=216 cm.

Step 3:Answer 216 cm.

Nonamiya [84]3 years ago
3 0

Answer:

216 square centimeter

Step-by-step explanation:

Area of a parallelogram = base * height

From the image,

base = 18cm

Height = 12cm

Area = 18* 12

= 216 square centimeter

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Which equation can be used to find X the measure of angle POQ?what is it’s measure?
faust18 [17]

Step-by-step explanation:

m<POR = 90°

=>m<POQ+m<QOR=90°

=>x+37°=90°

x=90°-37°=53°

option B

3 0
3 years ago
Perform the operation.<br> (8x2 – 7x – 2) – (6x2 – x + 3)
rewona [7]

Answer:

2 x² - 6x -5

Step-by-step explanation:

<u><em>Expansion:-</em></u>

Given that the expression

                    (8x²-7x-2)-(6x²-x+3)

                = 8x² - 6x² - 7x +x -2 -3

               = 2 x² - 6x -5

5 0
3 years ago
(a) Use a linear approximation to estimate f(0.9) and f(1.1). f(0.9) ≈ f(1.1) ≈ (b) Are your estimates in part (a) too large or
olasank [31]

Answer:

(Missing part of the question is attached)

L(x)=2x+3

Estimates are too large.

Step-by-step explanation:

Suppose the only information we know about the function is:

f(1)=5

where the graph of its derivative is shown in the attachment

<h3>(a)</h3>

If the function f\\ is differentiable at point x=1 , the tangent line to the graph of f at 1 is given by the equation:

y=f(1) +f'(1)(x-1)

So we call the linear function:

L(x)=f(1) +f'(1)(x-1)

We know the f(1)=5 as it is given in the question, and f'(1)=2 from the graph attached. Substitute in the equation of L(x).

L(x)=5+2(x-1)\\L(x)=5+2x-2\\L(x)=2x+3\\

<h3>(b)</h3>

At x=1,  f'(x) is positive but it is decreasing. However. if we draw the tangent lines, we see that the tangent lines are becoming less steeper, so the tangent lines lie above the curve f. Thus, The estimates are too large.

4 0
3 years ago
Pilar is playing with a motorized toy boat. She puts the boat in a lake and it travels 400m at a constant speed. On the way back
ankoles [38]

Answer:

The trip normally takes 8 minutes

Step-by-step explanation:

The given information states that the away distance the boat traveled = 400 m

The time traveled at the same initial  speed , v₁, by the boat on the way back = 2 minutes

The increase in speed of the boat by Pilar =  10 m/min

The new speed, v₂ = v₁ + 10

The time for the return trip, t₂ = 60 seconds (1 minute) faster than time for the trip, t₁

t₂ = t₁ - 1

Therefore we have;

v₁ × t₁ = v₁×2 + v₂×(t₂-2) = 400

v₁×2 + (v₁ + 10)×(t₂-2) = 400

(v₁ + 10)×t₂ - 20 = 400

But v₁ = 400/t₁ = 400/(t₂ + 1)

Which gives;

(400/(t₂ + 1) + 10)×t₂ - 20 = 400

10×(t₂²+ 36·t₂-2)/(t₂+1) = 400

10·t₂²+ 10·t₂-420 = 0

t₂²+ t₂-42 = 0

(t₂ - 7)(t₂ + 6) = 0

t₂ = 7 minutes or -6 minutes

Given that t₂ is a natural number, we have, t₂ = 7 minutes

Whereby, t₂ = t₁ - 1, we have;

7 =  t₁ - 1

t₁ = 1 + 7 = 8 Minutes

The trip normally takes 8 minutes

3 0
3 years ago
Use the distance formula, show that the points (4,0), (2,1), and (-1,-5) form the vertices of a right triangle
mario62 [17]

Step-by-step explanation:

The distance formula between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the points.

A(4,\ 0),\ B(2,\ 1),\ C(-1,\ -5)\\\\AB=\sqrt{(2-4)^2+(1-0)^2}=\sqrt{(-2)^2+1^2}=\sqrt{4+1}=\sqrt5\\\\AC=\sqrt{(-1-4)^2+(-5-0)^2}=\sqrt{(-5)^2+(-5)^2}=\sqrt{25+25}=\sqrt{50}\\\\BC=\sqrt{(-1-2)^2+(-5-1)^2}=\sqrt{(-3)^2+(-6)^2}=\sqrt{9+36}=\sqrt{45}

If a ≤ b < c are the sides of the right triangle, then

a² + b² = c²

\sqrt5

used (\sqrt{a})^2=a for a ≥ 0.

AB^2+BC^2=AC^2 therefore ΔABC is a right triangle.

6 0
3 years ago
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