The magnification is 0.54
Given,
The distance between object and concave lens, u = -21 cm
Focal length of the concave lens, f = -25 cm
Let m be the magnification.
m = v/u
Here v is the position of image.
We have to find v first.
By using lens equation we can determine v.
That is,
1/f = 1/v – 1/u
So,
- (1/25) = 1/v – (-1/21)
- (1/25) = 1/v + 1/21
1/v = - (1/25) – 1/21
1/v = (-25 – 21) / (21 x 25)
1/v = - (46/525)
Therefore v = - (525/46)
v = -11.41 cm
Now we have to find magnification, m.
m = v/u
= (-11.41) / (-21)
= 0.54
Here magnification is 0.54
Learn more about concave lens here: brainly.com/question/12944945
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Firstly, you need to combine like terms within that side of the equation.
Take -3x +9x and you’ll get 6x.
Next, combine like terms on the other side of the equation.
Take -5-1 and you’ll get -6
So far you should have:
6x+2=4x-6
Subtract 4x on each side!! Cancel 4x-4x! Solve 6x-4x!
Now you’ll get:
2x+2=-6
Subtract 2 on each side!!
Cancel out 2-2 and solve -6-2.
You should get:
2x=-8
Lastly, divide 2 on each side.
Cancel out 2/2 and solve 8/2.
Your final answer should be:
X = -4
Answer:
Part a) The inequality that represent the situation is
Part b) The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to 
Step-by-step explanation:
Let
x------> the length of the first wire
3x---> the length of the second wire
2(3x)=6x -----> the length of the third wire
Part a) WRITE AN *INEQUALITY* THAT MODELS THE SITUATION
we know that
The inequality that represent the situation is
Part b) WHAT ARE THE POSSIBLE LENGTHS OF THE SHORTEST PIECE OF WIRE?
we know that
The shortest piece of wire is the first wire
so
Solve the inequality
Divide by 10 both sides
The possible lengths of the shortest piece of wire are all positive real numbers less than or equal to
Answer:
72 I am pretty sure
Step-by-step explanation:
6 x 10 = 60 and 4 x 6 = 24 ÷ 2 = 12 = 72
