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3 years ago

What’s the solution

Mathematics

1 answer:

nata0808 [166]3 years ago

7 0

Answer:

We need more info

Step-by-step explanation:.

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The leftmost digits of rwo nunbers are 8 and 3 which one is greater

makvit [3.9K]

EIGHT WOULD BE GREATER

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3 years ago

Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth

taurus [48]

Answer:

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

We use the Method of Undetermined Coefficients.

We first solve the homogeneous differential equation y′′+4y=0.

$y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\$

It is a homogeneous solution:

$y_h(t)=c_1e^{-2i t}+c_2e^{2i t}$

Now, we finding a particular solution.

$y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\$

we get

$y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

So, solution of the differential equation is

$y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos 2x+c_1e^{-2it}+c_2e^{2it}\\$

7 0

3 years ago

Which is not a common factor of 15, 45,and 90

Naddika [18.5K]

Answer:

6/90/45/30/18/9/2

Step-by-step explanation:

15: 3/5/15/1

45: 45/1/9/5/15/3/

90: 90/1/9/10/45/2/15/6/3/30/5/18

7 0

3 years ago

An equivalent ratio for 7/14

motikmotik

Answer:

1/2

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

The difference of 15 and x is 12

gulaghasi [49]

Answer:

X is 3

Step-by-step explanation:

15-x=12

X=15-12

X=3

8 0

2 years ago