Answer:
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Step-by-step explanation:
Given;
The height function S(t) of the rocket as;
S(t) = -16t2 + 208t
The maximum altitude Smax, will occur at dS/dt = 0
differentiating S(t);
dS/dt = -32t + 208 = 0
-32t +208 = 0
32t = 208
t = 208/32
t = 6.5 seconds.
The maximum altitude Smax is;
Substituting t = 6.5 s
Smax = -16(6.5)^2 + 208(6.5)
Smax = 676 ft
the maximum altitude (height) the rocket will attain during its flight is 676 ft
Answer:
1241
Step-by-step explanation:
∴
L.C.M. of 28, 36 and 45 = 2 × 2 × 3 × 3 × 5 × 7 = 1260
∴
the required number is 1260 - 19 = 1241
Hence, if we add 19 to 1241 we will get 1260 which is exactly divisible by 28, 36 and 45.
What is the rest of the question
Answer:
sorry but idk
Step-by-step explanation:
Answer:
(3x+4b)(a-2y)
Step-by-step explanation:
(3ax-6xy)+(8by-4ab)
3x(a-2y) -4b(-2y+a)
(3x+4b) (a-2y)
