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e-lub [12.9K]
3 years ago
14

It takes a barber 12 minutes to shave a face and 30 minutes to give a haircut. The barber works for 6 hours straight and spends

twice as much time shaving faces as he does giving haircuts. If two of his customers get both a haircut and a shave, then how many customers does he see in total?
Mathematics
1 answer:
Mrrafil [7]3 years ago
7 0

Answer:

7 customers

Step-by-step explanation:

You might be interested in
X - 2y = 3<br> 5x + 3y = 2<br> The lines whose equations are shown intersect at which point?
Lady_Fox [76]

The point of intersection of the two lines is at (1,-1)

<h3>System of equation</h3>

The given system of expression is shown below

x - 2y = 3

5x + 3y = 2

The solution to the system of equation is the point of intersection

From equation 1

x = 3 + 2y

Substitute into 2

5(3+2y) + 3y = 2

15 +10y + 3y = 2

13y = -13

y = -1

Substitute y = -1 into 3

x = 3 + 2y

x = 3+(-2)

x = 1

Hence the point of intersection of the two lines is at (1,-1)

Learn more on system of equation here: brainly.com/question/25976025

#SPJ1

8 0
2 years ago
−4.2(−2.8+4.5)​ I think I know what the answer is but I just want to be 100% sure. Please solve this and tell me your answer. I
Talja [164]

Answer:

-7.14

Step-by-step explanation:

Evaluate

−4.2(−2.8 + 4.5)​

Open parenthesis

(-4.2 * -2.8) + (-4.2 * 4.5)

= (11.76) + (- 18.9)

= 11.76 - 18.9

= -7.14

NOTE:

Negative (-) × negative (-) = positive (+)

Positive (+) × positive (+) = positive (+)

Negative (-) × positive (+) = negative (-)

Positive (+) × negative (-) = negative (-)

7 0
3 years ago
Find the distance traveled by a particle with position (x, y as t varies in the given time interval. x = 3?sin2 t, y = 3?cos2 t,
ANTONII [103]
Assuming the particle's position is given by

\begin{cases}x(t)=3-\sin2t\\y(t)=3-\cos2t\\0\le t\le4\end{cases}

then the distance traveled over the interval is

\displaystyle\int_{t=0}^{t=4}\sqrt{\left(\dfrac{\mathrm dx(t)}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy(t)}{\mathrm dt}\right)^2}\,\mathrm dt
=\displaystyle\int_0^4\sqrt{(-2\cos2t)^2+(2\sin2t)^2}\,\mathrm dt
=\displaystyle\int_0^4\sqrt{4\cos^22t+4\sin^22t}\,\mathrm dt
=\displaystyle2\int_0^4\mathrm dt
=2(4-0)=8
5 0
3 years ago
Which is the product of (3)(7) and why?
irina [24]

Answer:

21

Step-by-step explanation:

8 0
3 years ago
What is the solution to -2(3x - 9) + 5x = -10?
sweet-ann [11.9K]
-2(3x - 9) + 5x = -10
-6x + 18 + 5x = -10
-6x + 5x = -10 - 18
-x = -28
x = 28 <===
6 0
3 years ago
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