Answer:
y(t)= 10 (2)^t
Step-by-step explanation:
If t is the number of years given then the expected number can be found by
y(t)= 10 (2)^t
where t takes the value 0,1,2,3, and so on.
Putting t= 0
y(t)= 10 (2)^t
y(0)= 10 (2)^0
y(0)= 10 For the start the number of deer are 10.
Putting t= 1
y(t)= 10 (2)^t
y(1)= 10 (2)^1
y(1)= 20 After 1 year it has doubled to 20
Putting t= 2
y(t)= 10 (2)^t
y(2)= 10 (2)^2
y(2)= 40 After 2 years it has again doubled to 40
Putting t= 3
y(t)= 10 (2)^t
y(3)= 10 (2)^3
y(3)= 80 After 3 years it has again doubled to 80
