This problem mentions 'CHOICE,' which means you need to share the several possible answers that came with this problem.
There is an upfront charge of $12 per car. Next, each person in the car is charged $1. Supposing that x people are in the car, then the total cost, C(x), is
C(x) = $12 + ($1)x. This is a linear function whose domain could be, for example, [0,6], assuming that 6 people could fit into the car.
We would have the following sample space:
(1, 1), (1, 2), (1, 3), (1, 4)
(2, 1), (2, 2), (2, 3), (2, 4)
(3, 1), (3, 2), (3, 3), (3, 4)
(4, 1), (4, 2), (4, 3), (4, 4)
Those give us these sums:
2, 3, 4, 5
3, 4, 5, 6
4, 5, 6, 7
5, 6, 7, 8
P(sum of 2) = 1/16 =0.0625
P(sum of 3) = 2/16 = 0.125
P(sum of 4) = 3/16 = 0.1875
P(sum of 5) = 4/16 = 0.25
P(sum of 6) = 3/16 = 0.1875
P(sum of 7) = 2/16 = 0.125
P(sum of 8) = 1/16 = 0.0625
Answer:
smaller number is 10
larger number is 39
Step-by-step explanation:
a = small number
b = larger number
a + b = 49
2a = 3b - 97
substitute 49-a into second equation for b
2a = 3(49-a) - 97
2a = 147 - 3a - 97
5a = 50
a = 10
b = 39
Answer:
Step-by-step explanation:
Each child received two pieces.
So total pieces received by 4 children = 4*2 = 8
Total pieces = 10 + 8 = 18
