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3 years ago

2 4/5 divided by 2/3

Mathematics

2 answers:

daser333 [38]3 years ago

5 0

Answer:

4.2 cuz yeah

Yeet :)

Molodets [167]3 years ago

3 0

Answer:

1 13/15

Step-by-step explanation:

Convert 2 4/5 into improper fraction =14/5

Make 2/3 and 14/5 with the same denominator

10/15 and 42/15

Flip 42/15 into 15/42

Then cross cancel

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The sum of four consecutive numbers is 230. What is the largest of these numbers

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Answer:

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4n = 224

n = 56 and largest number = 59

Step-by-step explanation:

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3 years ago

What is the image of the point (5, -3) after a reflection over the line y = x?

Musya8 [376]

Answer:

(-3,5)

Step-by-step explanation:

If the slope of y=x is 1, then you have to reflect over that line with a negative slope. It should reflect over to be (-3,5).

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3 years ago

Suppose the force acting on a column that helps to support a building is a normally distributed random variable X with mean valu

Sauron [17]

Answer:

(1) 0.4207

(2) 0.7799

Step-by-step explanation:

Given,

Mean value,

$\mu = 15.0$

Standard deviation,

$\sigma = 1.25$

(1) P(X ≥ 17.5) = 1 - P( X ≤ 17.5)

$= 1- P(\frac{x-\mu}{\sigma} \leq \frac{17.5-\mu}{\sigma})$

$=1-P(z\leq \frac{17.5 - 15}{1.25})$

$=1-P(z\leq \frac{2.5}{1.25})$

$=1-P(z\leq 2)$

$=1- 0.5793$ ( By using z-score table )

= 0.4207

(2) P(14 ≤ X ≤ 18) = P(X ≤ 18) - P(X ≤ 14)

$=P(z\leq \frac{18 - 15}{1.25}) - P(z\leq \frac{14 - 15}{1.25})$

$=P(z\leq \frac{3}{1.25}) - P(z\leq -\frac{1}{1.25})$

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= 0.9918 - 0.2119

= 0.7799

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3 years ago

Noah is deciding which of 2 juice containers he should buy. One container is in the shape of a cylinder with radius 3.5 centimet

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3 years ago

Health insurance benefits vary by the size of the company. The sample data below show the number of companies providing health i

telo118 [61]

Answer:

Step-by-step explanation:

a. The hypothesis of testing are

Null Hypothesis, H0: The health insurance coverage is independent of the size of the company.

Alternative hypothesis, H1: The health insurance coverage is not independent of the size of the company

The test statistics is calculated as

X² = ∑(Ei - Oi)² ≅X²(r-1)(c-1)

i Ei

where Oi's are the observed values and Ei's are the expected values,

E= row total × column total

total

The expected values are

Sizeof the Company

Health Insurance Small Medium Large Total

Yes 42 63 84 189

No 8 12 16 36

Total 50 75 100 225

Therefore, the test statistics is

X² =∑ (Ei -Oi)² =6.94 ≅ x²₂

i Ei

The critical value is found to be 5.99. Since test statistics > critical value, we reject H0 and conclude that the health insurance coverage is not independent of the size of the company.

The associated p-value is 0.031 (<0.05).

b. Percentage of employees lacking health insurance coverage is

Small 14/50 x 100 = 28%

Medium 10/75 x 100 = 13%

Large 12/100 x 100 = 12%

Hence depending on the above percentage, we can support the claim that the employees of small companies are more likely to lack health insurance coverage.

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3 years ago