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alina1380 [7]
3 years ago
9

2 4/5 divided by 2/3

Mathematics
2 answers:
daser333 [38]3 years ago
5 0

Answer:

4.2 cuz yeah

Yeet :)

Molodets [167]3 years ago
3 0

Answer:

1 13/15

Step-by-step explanation:

Convert 2 4/5 into improper fraction =14/5

Make 2/3 and 14/5 with the same denominator

10/15 and 42/15

Flip 42/15 into 15/42

Then cross cancel

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The sum of four consecutive numbers is 230. What is the largest of these numbers
vodka [1.7K]

Answer:

n + n+1 + n+2 + n+3 = 230

4n = 224

n = 56 and largest number = 59


Step-by-step explanation:


7 0
3 years ago
What is the image of the point (5, -3) after a reflection over the line y = x?
Musya8 [376]

Answer:

(-3,5)

Step-by-step explanation:

If the slope of y=x is 1, then you have to reflect over that line with a negative slope. It should reflect over to be (-3,5).

4 0
3 years ago
Suppose the force acting on a column that helps to support a building is a normally distributed random variable X with mean valu
Sauron [17]

Answer:

(1) 0.4207

(2) 0.7799

Step-by-step explanation:

Given,

Mean value,

\mu = 15.0

Standard deviation,

\sigma = 1.25

(1) P(X ≥ 17.5) = 1 - P( X ≤ 17.5)

= 1- P(\frac{x-\mu}{\sigma} \leq \frac{17.5-\mu}{\sigma})

=1-P(z\leq \frac{17.5 - 15}{1.25})

=1-P(z\leq \frac{2.5}{1.25})

=1-P(z\leq 2)

=1- 0.5793   ( By using z-score table )

= 0.4207

(2) P(14 ≤ X ≤ 18) = P(X ≤ 18) - P(X ≤ 14)

=P(z\leq \frac{18 - 15}{1.25}) - P(z\leq \frac{14 - 15}{1.25})

=P(z\leq \frac{3}{1.25}) - P(z\leq -\frac{1}{1.25})

=P(z\leq 2.4) - P(z\leq -0.8)

= 0.9918 - 0.2119

= 0.7799

8 0
3 years ago
Noah is deciding which of 2 juice containers he should buy. One container is in the shape of a cylinder with radius 3.5 centimet
Gelneren [198K]

Answer: The second container.

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8 0
3 years ago
Health insurance benefits vary by the size of the company. The sample data below show the number of companies providing health i
telo118 [61]

Answer:

Step-by-step explanation:

a. The hypothesis of testing are

Null Hypothesis, H0: The health insurance coverage is independent of the size of the company.

Alternative hypothesis, H1: The health insurance coverage is not independent of the size of the company

The test statistics is calculated as

X² =  <u>∑(Ei - Oi)²</u>  ≅X²(r-1)(c-1)

        i      Ei

where Oi's are the observed values and Ei's are the expected values,

E= <u>row total × column total</u>

            total

The expected values are

        Sizeof the Company  

Health Insurance    Small   Medium Large Total

Yes                             42     63          84           189

No                              8             12          16           36

Total                      50    75                  100           225

Therefore, the test statistics is

X² =∑ (<u>Ei -Oi)² </u>=6.94 ≅  x²₂

      i       Ei

The critical value is found to be 5.99. Since test statistics > critical value, we reject H0 and conclude that the health insurance coverage is not independent of the size of the company.

The associated p-value is 0.031 (<0.05).

b. Percentage of employees lacking health insurance coverage is

Small 14/50 x 100 = 28%

Medium 10/75 x 100 = 13%

Large 12/100 x 100 = 12%

Hence depending on the above percentage, we can support the claim that the employees of small companies are more likely to lack health insurance coverage.

8 0
3 years ago
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