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3 years ago

Solve by taking the square too of both sides. 3(c+3)^2-81=0

Mathematics

1 answer:

Norma-Jean [14]3 years ago

7 0

Answer:

x = -3 ±3sqrt(3)

Step-by-step explanation:

3(x+3)^2-81=0

Add 81 to each side

3(x+3)^2=81

Divide each side by 3

3/3(x+3)^2=81/3

(x+3)^2=27

Take the square root of each side

sqrt ((x+3)^2)=±sqrt(27)

x+3 =±sqrt(9*3)

x+3 =±sqrt(9)*sqrt(3)

x+3 =±3sqrt(3)

Subtract 3 from each side

x = -3 ±3sqrt(3)

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Ramiya is using the quadratic formula to solve a quadratic equation. Her equation is x = after substituting the values of a, b,

Stels [109]

Answer:

this is the answer

0 = x2 + 3x + 2

Step-by-step explanation:

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3 years ago

What is the expression in radical form?<br><br> (4x3y2)310

sertanlavr [38]

Given:

Consider the given expression is

$(4x^3y^2)^{\frac{3}{10}}$

To find:

The radical form of given expression.

Solution:

We have,

$(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}$

$(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

$(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}$ $[\because x^{\frac{1}{n}}=\sqrt[n]{x}]$

Therefore, the required radical form is $\sqrt[5]{8y^3}\sqrt[10]{x^9}$ .

8 0

4 years ago

How much is 80% from 250.00

rodikova [14]

If you need further help on how they got the answer, this equation will take more time, but it will also help you understand these types of problems. Part÷Whole=Percent÷100
Part= X because it is what you are trying to find.
Whole=250 because it is what you are taking the percentage of.
Percent=80
Now you have:
X÷250=80÷100
Set this up in fraction form and cross multiply.
You get:
100x=250×80
250×80=20,000
100x=20,000
X=200

3 0

3 years ago

Read 2 more answers

A time/motion word problem

andriy [413]

The two planes are flying on the two legs of a right triangle.
The straight distance between them is the hypotenuse of the triangle.

Since the speeds are in mph, let's work the time in hours.
Call the time 'H' that we're looking for.
It's the number of hours after they both take off that they're 650 miles apart.

After 'H' hours, the first plane has gone 500H miles north.
After 'H' hours, the second plane has gone 1200H miles east.
After 'H' hours, they are 650 miles apart.

Do you remember this for a right triangle ? ==> A² + B² = C²

(500H)² + (1200H)² = (650)²

250,000H² + 1,440,000H² = 422,500

1,690,000 H² = 422,500

H² = (422,500) / (1,690,000) = 0.25

H = √0.25 = 1/2 hour = 30 minutes

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4 years ago

Read 2 more answers

For f(x) = 2x +1 and g(x) = x^2-7, find (f/g) (x)

Rashid [163]

the answer is (f/g)(x) = 2(x^2 - 7) + 1
= 2x^2 - 14 + 1
= 2x^2 - 13

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3 years ago