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3 years ago

Given: ABCD is a square.

Mathematics

2 answers:

jonny [76]3 years ago

4 0

Answer:abc about

Step-by-step explanation: all of them are bad

Klio2033 [76]3 years ago

3 0

Answer:

The answers are:

Has two pairs of parallel sides

All four sides are congruent

Both pairs of opposite sides are congruent

There are right angles at all four vertices

The diagonals are perpendicular

The diagonals are congruent

The diagonals bisect each other

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Find the area of a triangle with a base of 27 feet and a height of 14 feet.

Burka [1]

It's D, since 27x14=378

3 0

4 years ago

Let u=(5,12) and c=-3. what is ||cu||

DedPeter [7]

||cu|| = |c| * |u| = c[ magnitude of vector sum of 5i + 12j ] = 3sqrt(5^2 + 12^2)

= 3sqrt(169) = 3(13) = 39 (answer)

3 0

3 years ago

Pls find x!!!!!!!!!!!!!!!!!!!!!

Andrews [41]

Answer:

120°

Step-by-step explanation:

The angle just below 'x' is 40° (alternate angles/parallel lines)

40 + x + 20 = 180 ( straight line)

x = 120°

6 0

2 years ago

Find the equation of the line that passes through (0, -3) and is parallel to

Tresset [83]

Hey there!

$\\$

Answer:

$\green{\boxed{\red{\bold{\sf{y = \dfrac{7}{6}x - 3}}}}}$

$\\$

Explanation:

To find the equation of a line, we first have to determine its slope knowing that parallel lines have the same slope.

Let the line that we are trying to determine its equation be $\: \sf{d_1} \:$ and the line that is parallel to $\: \sf{d_1} \:$ be $\: \sf{d_2} \:$ .

$\sf{d_2} \:$ passes through the points (9 , 2) and (3 , -5) which means that we can find its slope using the slope formula:

$\sf{m = \dfrac{\Delta y}{\Delta x} = \dfrac{\green{y_2} - \orange{y_1}}{\red{x_2} - \blue{x_1 }}}$

$\\$

⇒Subtitute the values :

$\sf{(\overbrace{\blue{9}}^{\blue{x_1}}\: , \: \overbrace{\orange{2}}^{\orange{y_1}}) \: \: and \: \: (\overbrace{\red{3}}^{\red{x_2}} \: , \: \overbrace{\green{-5}}^{\green{y_2}} )}$

$\implies \sf{m = \dfrac{\Delta y}{\Delta x} = \dfrac{\green{-5} - \orange{2}}{\red{ \: \: 3} - \blue{9 }} = \dfrac{ - 7}{ - 6} = \boxed{ \bold{\dfrac{7}{6} }}}$

$\sf{\bold{The \: slope \: of \: both \: lines \: is \: \dfrac{7}{6}}}$ .

Assuming that we want to get the equation in Slope-Intercept Form, let's substitute m = 7/6:

Slope-Intercept Form:

$\sf{y = mx + b} \\ \sf{Where \: m \: is \: the \: slope \: of \: the \: line \: and \: b \: is \: the \: y-intercept.}$

$\implies \sf{y = \bold{\dfrac{7}{6}}x + b}$ $\\$

We know that the coordinates of the point (0 , -3) verify the equation since it is on the line $\: \sf{d_1} \:$ . Now, replace y with -3 and x with 0:

$\implies \sf{\overbrace{-3}^{y} = \dfrac{7}{8} \times \overbrace{0}^{x} + b} \\ \\ \implies \sf{-3 = 0 + b} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \implies \sf{\boxed{\bold{b = -3}} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$