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ad-work [718]
3 years ago
12

Math Need Help

Mathematics
2 answers:
crimeas [40]3 years ago
8 0
Hi there! The answer is 5/6 hours (which is 50 minutes)

To find the total time Ann spent on her papers, we must add the fractions.
\frac{1}{3}  +  \frac{1}{2}  =  \frac{2}{6}  +  \frac{3}{6}  =  \frac{5}{6}

In the first step, we had to make the denominators the same. We need to use the LCM of the numbers 2 and 3. LCM(2,3) = 6.

In the second step we added the fractions. Remember that we only need to add the numerators (the denominator remains the same).

~ Hope this helps you!
ExtremeBDS [4]3 years ago
7 0
Hi there!

Total time spent by Ann on th' papers :-

\dfrac {1}{3} + \dfrac {1}{2} = \dfrac {2 + 3}{6} = \dfrac {5}{6}

Hence,
Ann's total time spent = \dfrac {5}{6} i.e. 50 minutes.

~ Hope it helps!
You might be interested in
Mathmatics 8th grade
Nady [450]

Answer:

A.\frac{3}{8} , \frac{1}{2} , 1 , \sqrt{2} , 4

Step-by-step explanation:

\frac{3}{8} < \frac{1}{2} \\\\\frac{1}{2} < 1\\\\1 < \sqrt{2} \\\\\sqrt{2} < 4

6 0
3 years ago
Read 2 more answers
If zn = z√, what value of n makes this equation true?
GarryVolchara [31]

Answer:

zn\:=\:z\sqrt{n^2}

Step-by-step explanation:

zn = z√?

√? = \frac{zn}{z}

√? = n

? = n²

Therefore z√n² makes the statement zn true

4 0
2 years ago
Read 2 more answers
Which polynomial is a difference of two squares? O x² – 16 O x² +16 O x² – 8 O x² + 8​
UNO [17]

Answer:

x²-16

Step-by-step explanation:

x²-16 =0

Add 16 to both sides

x²-16 + 16 = 0 + 16

Simplify

x²= 16

For x²=(fa) the solutions are x = √(fa), -√(fa)

X=√16 ,X= -√16

√16=4

-√16 = -4

x=4, x= -4

3 0
2 years ago
Help me this is due today!!!!!!!!
nadya68 [22]

Answer:

$70

Step-by-step explanation:

$12.60 / .18 = $70

I hope this is right, but I am thinking it is since you have to multiply by .18 to get the tip value.

4 0
3 years ago
On this graph, 4:00 p.m. occurs at 16 hours after midnight, and 6:00 p.m. occurs at 18 hours after midnight. Which statements ar
KatRina [158]

Answer:

TRUE OPTIONS ARE:

<em>"The temperature increased until 4:00 p.m. "</em>

<em>"The temperature decreased after 6:00 p.m. "</em>

<em>"The temperature increased more quickly between 12:00 p.m. and 4:00 p.m. than before 12:00 p.m."</em>

Step-by-step explanation:

<em>graph attached and complete question below:</em>

<em>Which statements are true about the temperatures Luis  recorded on the graph? Check all that apply. </em>

  • <em>The temperature increased until 4:00 p.m. </em>
  • <em>The temperature was not recorded between 4:00 p.m.  and 6:00 p.m. </em>
  • <em>The temperature decreased after 6:00 p.m. </em>
  • <em>The temperature increased and then decreased before  holding constant. </em>
  • <em>The temperature increased more quickly between 12:00 p.m. and 4:00 p.m. than before 12:00 p.m.</em>

<em />

Until 1600 hours, the graph increases, so we can say temperature increased until 4.00 pm (FIRST OPTION TRUE).

From 1600 to 1800 hours (4 - 6pm), the temperature stayed same (horizontal line). This doesn't mean the temperature wasn't recorded. (2nd OPTION FALSE).

After 1800 hours (6pm), the line goes downward, so temperature decreased after 6 pm. (3rd OPTION TRUE).

If you look at the temperature graph, we can see temperature increased, then increased more, then constant, then decreased. Thus the 4th option isnt true. (4th OPTION FALSE).

Before 12, the increase isn't as sharp as after 12. After 12 temperature increase has more slope, so this increase is more. (5th OPTION TRUE).

7 0
3 years ago
Read 2 more answers
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