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mote1985 [20]
2 years ago
15

All points of the step function f(x) are graphed.

Mathematics
2 answers:
astraxan [27]2 years ago
6 0

Answer:

\left \{ x|-4

First option is correct.

Step-by-step explanation:

Domain is the set of x values for which the function is defined.

Hence, in order to find the domain, we see at which x values the graph originates and at which value of x the graph terminates.

The piece wise function is graphed between the values -4 and 4.

There is a hole at x = -4 hence, we'll not include this point in domain.

There is a solid circle at x = 4 hence, we'll include this point in domain.

Therefore, the domain of f(x) is

\left \{ x|-4

First option is correct.

swat322 years ago
4 0
Your answer is the first option -4<x<_4
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Completely factored form of xy^3 – x^3y?
Zolol [24]

Answer:

xy(y - x)(y + x)

Step-by-step explanation:

take out a common factor xy from both terms

= xy(y² - x²)

y² - x² is a difference of squares and factors in general as (y - x)(y + x)

Hence

xy³ - x³y = xy(x - y)(x + y)



8 0
3 years ago
Suzy fills a 1 pint thermos with milk each day for lunch how many times will she be able to fill her thermos with 1/2 gallon of
pogonyaev
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6 0
3 years ago
Marcus needs to buy some cabin. At the nearest store, three bags of cat food cost $16.50. How much would Marco spend on five bag
Bumek [7]

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$82.5

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$16.50 * 5 = $82.5

6 0
2 years ago
Read 2 more answers
Find the volume of the cone. Round you’re answer to the nearest truth if necessary. Use 3.14
S_A_V [24]

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3 0
3 years ago
On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John
insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

Acceleration due to gravity, g = $12\ ft/s^2$

a). Therefore the maximum height he can jump on Mars is

     $H_{max}=\frac{v^2}{2g}$

     $H_{max} = \frac{(48)^2}{2 \times 12}$

               = 96 ft

b). Time he can stay in the air before hitting the ground is

   $T=\frac{2v}{g}$

  $T=\frac{2 \times 48}{12}$

     = 8 seconds

c).  Considering upward motion as positive direction.

     v = u + at

We find the time taken to reach the maximum height by taking v = 0.

     v = u + at

     0 = 16 + (12) t

     $t=\frac{16}{12}$

        $=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t =  $=\frac{4}{3} \ s$  , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$  feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

Therefore final velocity is = -16 ft/s

3 0
3 years ago
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