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Andrei [34K]
3 years ago
10

Can anyone help out with this?

Mathematics
1 answer:
galina1969 [7]3 years ago
6 0

9514 1404 393

Answer:

  (x, f(x)) = (1, 6), (2, 11), (3, 18), (4, 27)

Step-by-step explanation:

Each figure consists of two small squares and a square that has a side length of 1 more than the figure number. That is, ...

  f(x) = (x +1)^2 +2

You can count the squares in figures 1-3. Figure 4 will be 2 more squares than 5^2 = 25, so will be 27 squares.

  (x, f(x)) = (1, 6), (2, 11), (3, 18), (4, 27)

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Solve h = −16t2 + 36t + 4.
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I can do each of the things I asked above.
So, let's change this into vertex form:
h=-16t^2+36t+4
h=(-16t^2+36t)+4
h=-16(t^2-2.25t)+4
h=-16(t^2-2.25t+1.27-1.27)+4
h=-16(t^2-2.25t+1.27)+20.32+4
h=-16(t-1.125)^2+24.32
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<span>Answers may vary due to rounding

</span>Factored Form:
h = -16t^2 + 36t + 4
h = -4\left(4t^2-9t-1\right)

Quadratic Formula:
x =  \frac{-b +/- \sqrt{b^2-4(a)(c)}}{2a}
<span>h = -16t^2 + 36t + 4
</span>a = -16 b = 36 c = 4
h = \frac{-(36) +/- \sqrt{(36)^2-4(-16)(4)}}{2(-16)}
h = \frac{-36 +/- \sqrt{1552}}{-32}
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