Answer:
Check the explanation
Step-by-step explanation:
Let
and
be sample means of white and Jesse denotes are two random variables.
Given that both samples are having normally distributed.
Assume
having with mean
and
having mean 
Also we have given the variance is constant
A)
We can test hypothesis as

For this problem
Test statistic is

Where

We have given all information for samples
By calculations we get
s=2.41
T=2.52
Here test statistic is having t-distribution with df=(10+7-2)=15
So p-value is P(t15>2.52)=0.012
Here significance level is 0.05
Since p-value is <0.05 we are rejecting null hypothesis at 95% confidence.
We can conclude that White has significant higher mean than Jesse. This claim we can made at 95% confidence.
Answer:
I will say C, because tossing a coin twice has two outcomes. H is for heads while T is for heads. Tell me if I'm right.
Step-by-step explanation:
Area de la base es un hexagono: Nota: asumiendo que 39 cm son el lado de un hexagono. Menuda pizza.
A = 3*sqrt(3)/2*a^2 = 3*sqrt(3)/2*39^2 = 3951.67391746839972 cm^2
Hay dos base y tapa, doble:
7903.34783493679944 cm^2
Luego los lados verticales:
6 * 39 * 4.7 = 1099.8 cm^2
TOtal = 9003.14783 = 9003.147 cm^2 = 9003.15 cm^2
The second in the top row is this:
42.4-1.5(TIMES)3.1
42.4-46.5
-4.1
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