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Mumz [18]
3 years ago
11

Use the Counting Principle to find the probability. Choosing the 7 winning lottery numbers when the numbers are chosen at random

from 0 to 9
Mathematics
2 answers:
frozen [14]3 years ago
7 0

Answer:   120

<u>Step-by-step explanation:</u>

Since the order of the numbers doesn't matter we can use the formula:

\dfrac{n!}{r!(n-r)!}\quad \text{where n is the quantity of items and r is the quantity chosen}\\\\\text{In this problem, there are 10 numbers (n = 10) and 7 to be chosen (r = 7)}\\\\_{10}C_{7}=\dfrac{10!}{7!(10-7)!}\\\\.\qquad=\dfrac{10!}{7!3!}\\\\.\qquad=\dfrac{10\times 9\times 8\times 7!}{7!\times 3\times 2\times 1}\\\\.\qquad=10\times 3\times 4\\\\.\qquad=120

otez555 [7]3 years ago
4 0

Answer:

1/10,000,000  (gradpoint)

Step-by-step explanation:

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nalin [4]
The answer to your question is 3
7 0
3 years ago
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Pizzeria Napoli sells a round pizza with diameter 16 inches and a square pizza with side length 15 inches. Which of the two shap
zavuch27 [327]

Answer: Square, 24 square inches

Step-by-step explanation:

Given

Diameter of round pizza d=16\ in.

Side of square pizza a=15\ in.

Area of circle \pi r^2

The area of a square is a^2

\therefore \text{Area of round Pizza}=\pi \times (\frac{16}{2})^2\\\Rightarrow A_1=\pi \times 8^2=201.088\ in.^2

The area of square pizza is

A_2=15^2=225\ in.^2

Clearly, the area of square pizza is more and the difference in their area is

\Rightarrow A_2-A_1=225-201.088=23.91\approx\ 24\ in.^2

6 0
2 years ago
. Quantas senhas com 4 algarismos diferentes podemos escrever com os algarismos 1, 2, 3, 4, 5, 6?
ruslelena [56]

Answer:

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

Step-by-step explanation:

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

  • Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
  • Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
  • Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
  • Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

So, the number of passwords with 4 different digits we can write = 6 \times 5 \times 4 \times 3  = 360 possibilities.

Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

4 0
2 years ago
2<br> 2. Evaluate (a + y)+ 2y if a = 5 and y = -3.<br> F 58<br> G -2<br> H 70<br> J 10
NARA [144]
<h3>Answer:  G) -2</h3>

=======================================================

Explanation:

I'm assuming you meant to say (a+y)^2 + 2y

Replace each copy of 'a' with 5. Replace each copy of 'y' with -3. Use PEMDAS to simplify.

(a+y)^2 + 2y

(5 + (-3))^2 + 2(-3)

(5-3)^2 + 2(-3)

(2)^2 + 2(-3)

4 + 2(-3)

4 - 6

-2

So (a+y)^2 + 2y = -2 when a = 5 and y = -3.

3 0
3 years ago
Cressida decided to save a part of her income in a savings account that compounds interest every four months. Her account balanc
hichkok12 [17]
The answer is "<span>the number of times the account compounds interest</span>".
The general formula is the following:
3,545(1+r)^n
wherein r is the interest rate compound each four months. 
Since there is 3*4 months in a year, then each year we compute the interest Three time, there where the factor 3 comes. 
6 0
3 years ago
Read 2 more answers
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