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Mumz [18]
3 years ago
11

Use the Counting Principle to find the probability. Choosing the 7 winning lottery numbers when the numbers are chosen at random

from 0 to 9
Mathematics
2 answers:
frozen [14]3 years ago
7 0

Answer:   120

<u>Step-by-step explanation:</u>

Since the order of the numbers doesn't matter we can use the formula:

\dfrac{n!}{r!(n-r)!}\quad \text{where n is the quantity of items and r is the quantity chosen}\\\\\text{In this problem, there are 10 numbers (n = 10) and 7 to be chosen (r = 7)}\\\\_{10}C_{7}=\dfrac{10!}{7!(10-7)!}\\\\.\qquad=\dfrac{10!}{7!3!}\\\\.\qquad=\dfrac{10\times 9\times 8\times 7!}{7!\times 3\times 2\times 1}\\\\.\qquad=10\times 3\times 4\\\\.\qquad=120

otez555 [7]3 years ago
4 0

Answer:

1/10,000,000  (gradpoint)

Step-by-step explanation:

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Answer:

C.) 2\sqrt{34}

Step-by-step explanation:

<em>You must use the pythagorean theorem</em>

the distance on the x axis (or a) is 6

the distance on the y axis (or b) is 10

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3 years ago
What is the square root of m6?
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 the answer would be M^3
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Answer:

They both have no possible solution.

Step-by-step explanation:

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3 years ago
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Noah wants to put $1,000 in a savings account with a 1.5% annual interest rate. How much more money will he have after one year
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If you put $1000 for monthly interest, the saving account would become: ($1000*(100%+0.125%)= $1000*1.0151035559= $1015.10

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6 0
3 years ago
Need Help! I don't get it
serious [3.7K]
Well hmmm let's say you take the car and go in the city for 60 miles with it, well, the car can do 60 miles per gallon, since you just drove it for 60 miles, you only spent 1 gallon of gasoline then.

that only happens if you drive it for 60 miles, what if you drive it for more, let's do a quick table on that,

\bf \begin{array}{ccll}&#10;miles&cost\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;60&3.6(1)\\\\&#10;&3.6\left( \frac{60}{60} \right)\\\\&#10;120&3.6(2)\\\\&#10;&3.6\left( \frac{120}{60} \right)\\\\&#10;180&3.6(3)\\\\&#10;&3.6\left( \frac{180}{60} \right)&#10;\end{array}

and so on, now let's check if you less than 60 miles,

\bf \begin{array}{ccll}&#10;miles&cost\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;40&3.6\left( \frac{40}{60} \right)\\\\&#10;20&3.6\left( \frac{20}{60} \right)\\\\&#10;10&3.6\left( \frac{10}{60} \right)&#10;\end{array}

so, if you divide the amount of miles driven, by 60, when you have driven it for 120 miles, 120/60 is just 2, and the cost is for 2 gallons, or 3.6 * 2, which is 7.2 bucks, for 180 miles is 180/60 or 3 gallons for 3.6 * 3 bucks, and so on.

now, what if you drive it instead for "m" miles?

\bf \begin{array}{ccll}&#10;miles&cost\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;m&3.6\left( \frac{m}{60} \right)\\\\&#10;\end{array}\implies c=3.6\left( \cfrac{m}{60} \right)\implies c=\cfrac{3.6m}{60}&#10;\\\\\\&#10;c=\cfrac{3.6}{60}m\implies c=0.06m
3 0
3 years ago
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