Question

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Answer 1

Answer:

$\frac{2m-1}{5}$

Step-by-step explanation:

$2\left(\frac{1}{5}m-\frac{2}{5}\right)+\frac{3}{5}\\\\2\left(\frac{1}{5}m-\frac{2}{5}\right)=2\left(\frac{m}{5}-\frac{2}{5}\right)\\\\\frac{m}{5}-\frac{2}{5}=\frac{m-2}{5}\\\\=\frac{2\left(m-2\right)}{5}+\frac{3}{5}\\\\\mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\\\=\frac{2\left(m-2\right)+3}{5}\\\\\mathrm{Expand}\:\left(m-2\right)\cdot \:2+3:\quad 2m-1\\\\=\frac{2m-1}{5}$

Answer 2

Answer:

2/5m - 1/5

Step-by-step explanation:

2(1/5m - 2/5) + 3/5

= 2/5m - 4/5 + 3/5

= 2/5m - 1/5