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andrew-mc [135]
3 years ago
14

The diagram shows two parallel lines and transversal. If the measure of <6 is 140, what is the measure of <1?

Mathematics
2 answers:
alexandr402 [8]3 years ago
5 0
Angles 6 and 3 are supplementary.  If angle 6 is 140, then angle 3 is 40.  Because those lines are parallel and cut by a transversal, then angles 3 and 1 are corresponding and congruent.  That means that angle 1 measures 40° also.  Choice D.
VladimirAG [237]3 years ago
3 0

Answer:

(D)

Step-by-step explanation:

Given: It is given that ∠6 measures 140°.

To find: The measure of ∠1.

Solution:

It is given that ∠6 measures 140° and since there are two parallel lines which are cut by a transversal, then using the properties of parallel lines, we have

m∠6=m∠2(Alternate interior angles)

Therefore, m∠6=m∠2=140°

Also, m∠2 and m∠1 forms the linear pair, therefore

m∠1+m∠2=180°(Linear pair)

⇒m∠1+140°=180°

⇒m∠1=180-140

⇒m∠1=40°

Thus, the measure of ∠1 is 40°.

Hence, option D is correct.

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Step-by-step explanation:

Question 7:

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Therefore using distance formula, we get:

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You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta
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Answer:

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

m = -\frac{\cos 2\theta}{\sin \theta}

The tangent line is horizontal when m = 0. Then:

\cos 2\theta = 0

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\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right), for all i \in \mathbb{N}_{O}

\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}, for all i \in \mathbb{N}_{O}

The first four solutions are:

x:   \sqrt{2}   -\sqrt{2}  -\sqrt{2}  \sqrt{2}

y:     1        -1        1     -1

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

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