Answer:
-1.92 cm³
Step-by-step explanation:
The formula for the volume of a cube in terms of side length is ...
V = s³
Then the first-order approximation of volume for a small change ∆s in side length is ...
V(s +∆s) ≈ V(s) + V'(s)·∆s
and the change in volume is ...
∆V ≈ V(s +∆s) -V(s) = V'(s)·∆s
The derivative V'(s) is ...
V'(s) = 3s²
so the change in volume for s = 8 cm and ∆s = -0.01 cm is ...
∆V ≈ 3s²·∆s = 3(8 cm)²(-0.01 cm) = -1.92 cm³
The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.
<h3>What is the distance the spaceship travels in 4 minutes?</h3>
The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;
Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.
Consequently, we can evaluate the distance travelled after 4 minutes as;
Distance = 200 × 4 = 800mi.
Ultimately, the distance travelled per minute by the spaceship is; 800mi.
Remarks:
600 miles
520 miles
800 miles
1,080 miles
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Answer:
B
Step-by-step explanation:
Trust me on this one..
Answer:
180
Step-by-step explanation:
calculator.