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photoshop1234 [79]

3 years ago

8

consider quadrilateral ABCD as graphed above. rotate ABCD 90° clockwise about the origin, then dilate with a scale factor of 3/2

with the origin as the center. find the y-values of the coordinates for A”, B”, C”, and D”.

2 answers:

saw5 [17]3 years ago

5 0

Answer:

A”=three possible answers (10.5) (21/2) or (10 1/2)

B”=9

C”=3

D”=(4.5) (9/2) or (4 1/2)

Step-by-step explanation: just cause

11111nata11111 [884]3 years ago

3 0

Answer:

A" (4.5 , 10.5)

B" (7.5 , 9)

C" (7.5 , 3)

D" (4.5 , 4.5)

Step-by-step explanation:

<em>I did the work and got it right lol.</em>

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What equation represents an exponential function that passes through the point (2, 80)?

Marina86 [1]

Answer:

$f(x) = (4\sqrt{5})^{x}$

Step-by-step explanation:

The exponential function looks like the following: $f(x) = b^{x}$ .

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3 years ago

If RX=4 and XS=9, then XT=<br> And how do you get it?

konstantin123 [22]

Answer:

XT=6 units

Step-by-step explanation:

The picture of the question is the attached figure

step 1

In the right triangle RST

Applying the Pythagorean theorem

$RS^2=RT^2+TS^2$

we have

$RS=RX+XS=4+9=13\ units$ ---> by segment addition postulate

substitute

$RT^2+TS^2=169$ ----> equation A

step 2

In the right triangle RTX

Applying the Pythagorean theorem

$RT^2=RX^2+XT^2$

we have

$RX=4\ units$

substitute

$RT^2=4^2+XT^2$

$RT^2=16+XT^2$

$XT^2=RT^2-16$ ----> equation B

step 3

In the right triangle XTS

Applying the Pythagorean theorem

$TS^2=XS^2+XT^2$

we have

$XS=9\ units$

substitute

$TS^2=9^2+XT^2$

$TS^2=81+XT^2$

$XT^2=TS^2-81$ ----> equation C

step 4

equate equation B and equation C

$TS^2-81=RT^2-16$

$TS^2-RT^2=81-16$

$TS^2-RT^2=65$ ----> equation D

step 5

Solve the system

$RT^2+TS^2=169$ ----> equation A

$TS^2-RT^2=65$ ----> equation D

Solve by elimination

Adds equation A and equation D

$RT^2+TS^2=169\\TS^2-RT^2=65\\---------\\TS^2+TS^2=169+65\\2TS^2=234\\TS^2=117$

Find the value of RT^2

$RT^2+117=169\\RT^2=52$

step 6

Find the value of XT

equation C

$XT^2=117-81\\XT^2=36\\XT=6\ units$

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