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spin [16.1K]
3 years ago
12

John rented a bike from carlos' bikes it costs $19 plus $4 per hour if john paid $35 how many hours did he rent the bike

Mathematics
1 answer:
ss7ja [257]3 years ago
4 0
You can write this as an equation. P(price) = 4h(hours) +19. We know that P=35. If you plug it in, 35 = 4h +19. Subtract both sides by 19 to get 16 = 4h. Divide both sides by 4, and you get 4 = h, or the amount of hours, John rented the bike.
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Well each angle in a rectangle is 90°, so if x is an angle, it's 90°

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After a shopping spree at Target, John realized he spent three times more money than his brother Mike. They spent a total of $16
PSYCHO15rus [73]

Answer:

John spent around $53

Step-by-step explanation:

The equation is 3x=160

Since the "x" is already by itself on one side, divide 160 by 3

160÷3=53.333⇒

Now if that's not the way IT CAN ALSO BE:

30x3+70=160! That means John spent $90

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20 pts<br><br><br>evaluate: 48 divided by ( 17 - 15) ^3 - 5<br><br><br><br>help​
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8 0
2 years ago
A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
3 years ago
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inysia [295]
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attached is a file/ picture i made in google images of a graph of it, i explain the steps as well.
id appreciate a brainliest since the drawing took a good 15 minutes but its up to you! Hope i helped.</span></span>

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