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scoundrel [369]
3 years ago
10

Find the perimeter of a rhombus whose diagonals are

Mathematics
1 answer:
mojhsa [17]3 years ago
5 0

Answer:

Rhombus Side = sqr root [(34 / 2)^2 + (30 / 2)^2]

Rhombus Side = sqr root [17^2 + 15^2]

Rhombus Side = sqr root [289 + 225}

Rhombus Side = sqr root [514]

Rhombus Side = 22.6715680975

Rhombus Perimeter = side * 4 = 90.68627239  cm

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Given the function g is defined as follows.

g(x) = 2x²+7

If the graph is translated by 5units vertically downwards, this means that the function will be reduced by 5 units to have;

h(x) =  2x²+7 - 5

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3 0
2 years ago
What does 21÷3+(3×9)×9+5 equal? show work below plz
igor_vitrenko [27]
3x9=27
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so
7+27x9+5
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6 0
3 years ago
Read 2 more answers
Question 1:
ELEN [110]

Answer:

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Step-by-step explanation:

To find people who do use the waterslide and/or the sauna subracter 43 from 155 to get 112.

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To find people who use both the waterslide and the sauna subtract 15 from 43 to get 28.

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5 0
2 years ago
If you have 3/8 of one pie what does the denominator tells you
Viktor [21]
The denominator tells you the total amount of pieces.
8 0
2 years ago
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Gnom [1K]

Answer:

sin p -21/29

cos q 21/29 so here you go °~sohcahtoa~°

Step-by-step explanation:

sin means you find the soh part so you look for the oppisite over hyponuse

and for cos your looking for cah part so you find the adjsent over hypotnuse so the ansers is 21/29

4 0
3 years ago
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