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scoundrel [369]
3 years ago
10

Find the perimeter of a rhombus whose diagonals are

Mathematics
1 answer:
mojhsa [17]3 years ago
5 0

Answer:

Rhombus Side = sqr root [(34 / 2)^2 + (30 / 2)^2]

Rhombus Side = sqr root [17^2 + 15^2]

Rhombus Side = sqr root [289 + 225}

Rhombus Side = sqr root [514]

Rhombus Side = 22.6715680975

Rhombus Perimeter = side * 4 = 90.68627239  cm

Step-by-step explanation:

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Triangle ABC is dilated to create triangle DEF on a coordinate grid. You are given that angle A is congruent to angle D. What ot
Marina CMI [18]

Answer:

They must meet at least three requirements like those in the explanation.

Step-by-step explanation:

-The other angles are also corresponding for example: B is congruent to E and C to F.

- Its sides are proportional to each other

-These two triangles can have the same shape no matter what size each one is

4 0
2 years ago
HELPP, Lines parallel, Perpendicular, Neither? URGENT HELPPP.
VLD [36.1K]

Answer:

perpendicular I believe

Step-by-step explanation:

I'd plot the points and make a line using a ruler to check though.

8 0
2 years ago
Simply the expression 2(10)+2(x+4)
postnew [5]

Step-by-step explanation:

2(10)+2(x+4)

20 + 2x + 8

20 +8 +2x

28+2x

5 0
2 years ago
Read 2 more answers
X – 1 + 2x ≤ x + 3 <br> --- --- <br> 2 4
Paraphin [41]
<span>X – 1 + 2x ≤ x + 3 
--- --- 
2 4=7658</span>
5 0
3 years ago
If EF=2x-12, FG= 3x-15, and EG=23, find values of x, EF, and FG
velikii [3]

we have that


*-------------------------*--------------------------------*

E                            F                                     G


EF=2x-12

FG= 3x-15

EG=23


we know that


EF + FG = EG


so

[2x - 12] + [3x - 15] = 23 simplify

5x - 27 = 23 add 27 to both sides

5x = 50 divide both sides by 5

x = 10

EF=2x-12-------> EF=2*10-12-------> EF=8

FG= 3x-15------> FG=3*10-15------> FG=15



therefore


the answer part a) is

the value of x is 10


the answer part b) is

the value of EF is 8


the answer part c) is

the value of FG is 15

6 0
3 years ago
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