Answer:
Let the speed of the train be x km/h.
Case 1:
Distance = 288 km
Speed = x km/h
Time = Distance/Speed
= 288/x h
Case 2:
Distance = 288 km
Speed = (x+4) km/h
Time = 288/x + 4 h
Since 288/x > 288/x + 4
288/x - 288/x+4 = 1
288[1/x - 1/x+4 ] = 1
[ x + 4 - x / x(x + 4) ] = 1/288
[4 / x^2 + 4x ] = 1/288
x^2 + 4x = 1152
x^2 + 4x - 1152 = 0
x^2 + 36x - 32x - 1152 = 0
x(x + 36) - 32(x + 36) = 0
(x + 36)(x - 32) = 0
x + 36 = 0 , x - 32 = 0
x = -36 , x = 32
x = -36 , rejected since speed cannot be negative.
Therefore , speed of the train = 32 km/h
There are 2 significant figures (sig figs) which are the two '5' digits. The zeros aren't considered sig figs because we can write the number as 5.5 * 10^8 to represent the exact same idea. The 0's are simply placeholders to tell how big the number is, not necessarily how accurate it is. If the 0s were between the decimal point and a nonzero value, then the 0s would be significant. If the 0s were to the right of the decimal, then they would be significant.
Answer: 2
Answer:
c - 7 < -18
Step-by-step explanation:
Seven subtracted from c : c - 7
c - 7 < -18
Answer:
If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.
