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scoundrel [369]
3 years ago
9

Describe the two situations when you can use the Law of Cosines.

Mathematics
1 answer:
Tasya [4]3 years ago
6 0
We use the law of Cosines to be able to find : 1. The measure of the third side, when the measure of two sides and the included angle of a triangle ABC are known. 2. The measure of any angle, when the measure of the three sides of a triangle ABC are known.




The Law of Cosines is c² = a² + b² - 2abcosΘ. It has four variables; a, b, c and Θ. Whenever you have a triangle with three of these variables known, use the Law of Cosines to calculate the unknown variable.
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16. A rectangle's area is 18 m². Its perimeter is 18
Yanka [14]
Answer is (B) 6
Reason
3 x 6 = 18 (area)
3 + 3 + 6 + 6 = 18 (perimeter)
6 0
2 years ago
Read 2 more answers
The simple interest on 400 invested for 4 month was 12.what is the yearly rate of interest​
lukranit [14]

Answer:

9%

Step-by-step explanation:

If you get 12 for 4 months, then you get 36 for the year/12 months

Annual interest is $12 x 3 Months =36

36/400=9%.

6 0
3 years ago
The first term of a sequence is -12. The recursive formula for the sequence is an = an-1 + 9. What are the next 3 terms in the s
Bess [88]
The next three terms are: -3, 6, and 15

To get each new term, we simply add 9 to the last term. So we add 9 to -12 to get -3. Then we add 9 to -3 to get 6. Finally we add 9 to 6 to get 15

In other words,
first term = -12
second term = first term+9 = -12+9 = -3
third term = second term + 9 = -3+9 = 6
fourth term = third term + 9 = 6+9 = 15

This process repeats forever though we only need three terms in this case.

So that's why the answer is the three values -3, 6 and 15
8 0
3 years ago
Need help with finding my solution and graphing !
konstantin123 [22]

Answer:

Step-by-step explanation:

Both the equations that you modelled are correct.

Use the substitution method to solve the system of equations

R+C = 526\\5R+4C=2327\\

Take the first equation

R+C=526\\C=526-R

Now this becomes our third equation and now insert it into our second equation

5R+4C=2327\\5R+4(526-R)=2327\\5R+2104-4R=2327\\R=2327-2104\\R=223

Now insert R = 223 in any equation. Lets insert it into equation number three

C=526-R\\C=526-223\\C=303

So 223 number of roll papers were sold and 303 number of candles were sold.

I have attached the graph below check it out.

Where both the equations of line intersect is our solution thus we can confirm that our answer is correct.

7 0
3 years ago
Find the exact values of the six trigonometric functions of 0
siniylev [52]

Complete question is;

Find the exact values of the six trigonometric functions 0 if the terminal side of 0 in standard position contains the points(-5,-4).

Answer:

Sin θ = -4/√41

Cos θ = -5/√41

tan θ = 4/5

Cosec θ = (√41)/-4

Sec θ = (√41)/-5

Cot θ = 5/4

Step-by-step explanation:

Now, we are given the point (-5, -4)

These are x and y points.

They will form a triangle and we know that from pythagoras theorem;

x² + y² = r²

Where r is the distance between the point and the origin

Thus;

r² = (-5)² + (-4)²

r² = 25 + 16

r = √41

So, y is the opposite side of the triangle while x is the adjacent side with r being the hypotenuse.

Thus, the trigonometric ratios are;

Sin θ = opp/hyp = -4/√41

Cos θ = adj/hyp = -5/√41

tan θ = opp/adj = -4/-5 = 4/5

Cosec θ = 1/Sin θ = 1/(-4/√41) = (√41)/-4

Sec θ = 1/cos θ = 1/(-5/√41) = (√41)/-5

Cot θ = 1/tan θ = 1/(4/5) = 5/4

4 0
3 years ago
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