Note that the area of a square is: A = s² (s being side). Also note that all the sides of the square are congruent and have the same measurement.
Plug in 37 for A
37 = s²
Isolate the s. Note the equal sign. What you do to one side, you do to the other. Root both sides
√37 = √s²
s = √37
Change the root to a decimal
s = √37 = ~6.1 (rounded to the nearest tenth)
6.1 in is your answer
hope this helps
<span>Let's solve your equation step-by-step.
-x^2 = -36
</span><span>Step 1: Divide both sides by -1.
</span><span>-x^2/-1 = -36/-1
x^2 = 36
</span><span>Step 2: Take square root.
</span>x=<span>±<span>√<span>36
</span></span></span><span>x=<span><span>6 or </span>x</span></span>=<span>−<span>6
</span></span><span>
Answer: </span><span>x=<span><span>6<span> or </span></span>x</span></span>=<span>−<span>6
</span></span><span>
I hope this helps you! :)
</span>
Answer:
IQR is 3.5
Step-by-step explanation:
<u>Step 1: Organize the numbers in numerical order</u>
0,0,2,2,3,4,6,8
<u>Step 2: Break the set up into quartiles (4 parts)</u>
0 0 | 2 2 | 3 4 | 6 8
<u>Step 3: Find the average of each quartile</u>
0 | 2 | 3.5 | 7
<u>Step 4: Find the IQR (Q3-Q1)</u>
3.5-0=3.5
Therefore, the IQR is 3.5
Answer:
x = -2i and x = 2i
x = 3 and x = - 3
Step-by-step explanation:
x^4 - 5x^2 - 36 = 0
let u = x^2 and substitute
we have:
u^2 - 5u - 36 = 0
(u - 9)(u + 4) = 0
u = 9 and u = - 4
substitute back for u
x^2 = 9
x = 3 and x = - 3
x^2 = -4 -- i am going to assume you've learned imaginary numbers; otherwise, you cannot take the square root of a negative number.
x = -2i and x = 2i