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Charra [1.4K]
4 years ago
12

Multiply (4+I)(1-5i)

Mathematics
1 answer:
Svetllana [295]4 years ago
6 0
The rule to remember for this problem is: i^2 = -1
(4 + i)(1 - 5i)
4 - 20i + i - 5i^2
4 - 19i + 5
9 - 19i
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Which of the following is 38/6 converted to a mixed number
Monica [59]
6 goes into 38 6 times (6 * 6 = 36). We can bring out a whole number of 6 into our mixed number. Now, we have 2/6 left over. That can be reduced to 1/3. Your mixed number is 6\frac{1}{3}
7 0
3 years ago
What is double of 16
m_a_m_a [10]

Answer:

32

Step-by-step explanation:

16+16=32

or you can say 16*16=32

8 0
3 years ago
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The cost, C, to produce b baseball bats per day is modeled by the function C(b) = 0.06b2 – 7.2b + 390. What number of bats shoul
kozerog [31]

Check the picture below, that's just an example of a parabola opening upwards.

so the cost equation C(b), which is a quadratic with a positive leading term's coefficient, has the graph of a parabola like the one in the picture, so the cost goes down and down and down, reaches the vertex or namely the minimum, and then goes back up.

bearing in mind that the quantity will be on the x-axis and the cost amount is over the y-axis, what are the coordinates of the vertex of this parabola?  namely, at what cost for how many bats?

\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ C(b) = \stackrel{\stackrel{a}{\downarrow }}{0.06}b^2\stackrel{\stackrel{b}{\downarrow }}{-7.2}b\stackrel{\stackrel{c}{\downarrow }}{+390} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)

\bf \left( -\cfrac{-7.2}{2(0.06)}~~,~~390-\cfrac{(-7.2)^2}{4(0.06)} \right)\implies (60~~,~~390-216) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (\stackrel{\textit{number of bats}}{60}~~,~~\stackrel{\textit{total cost}}{174})~\hfill

6 0
3 years ago
Match these units :) *pls answer *
Oxana [17]
Do you have a picture to show so that I can help?<3
4 0
3 years ago
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Given: sin = 4/5 and cos x = -5/13 ; evaluate the following expression. Cos 2x
Nitella [24]

For every possible angle x, the fundamental law of trigonometric states that

\sin^2(x)+\cos^2(x) = 1

In your case, the inputs you provided would lead to

\dfrac{16}{25}+\dfrac{25}{169} = \dfrac{3329}{4225} \approx 0.8 \neq 1

So, it is not possible that, for a certain angle x, we have

\sin(x) = \dfrac{4}{5},\quad \cos(x) = -\dfrac{5}{13}

5 0
3 years ago
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