Answer: 82°
Step-by-step explanation:
<CDE = far arc - near arc / 2
i.e
<CDE = arcCBE - arcCE / 2
arcCE = 98°
arcCBE = 360° - 98° = 262°
<CDE = 262° - 98° / 2
<CDE = 164 / 2
<CDE = 82°
Therefore the measure of < CDE is 82°
You have to replace d woth 3 in formula
7d^2+10=7*(3)^2+10=7*9+10=63+10=73
d is the correct answer
Answer:
50
Step-by-step explanation:
take the arc degrees (100) and divide by 2
Inscribed angles are 1/2 of the created arc degrees
Answer:
373.8mmHg
Step-by-step explanation:
a =height (in km) above sea level,
the pressure P(a) (in mmHg) is approximated given as
P(a) = 760e–0.13a .
To determine the atmospheric pressure at 5.458 km, then we will input into the equation
P(5.458km) = 760e–0.13a .
= 760e^(-0.13×5.458)
=760e^-(0.70954)
= 760×0.4919
=373.8mmHg
Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg
Answer:
1. area = 16.492
2. area = 19.798
3. area = 15.874
4. area = 13.555
5. area = 12.349
6. area = 24.37
<em>good luck, i hope this helps :)</em>
