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3 years ago

The ratio of boys to girls at King Middle school is 3:2. What is the ratio of girls to all students?

1 answer:

8 0

The answer is: " 2 :5 " ; or, write as: " 2/5 " .
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The ratio of 'girls' to 'all students' is: "2: 5 " ; or, write as: " 2/5 ".
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Explanation:
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Given: The ratio of boys to girls is: " 3:2 " .

Problem: Find the ratio of "girls" to "all students:
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Note: This ratio of "boys to girls", which is " 3 : 2 " ;
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→ can be expressed as " 3x: 2x" ;

in which the total number of students is: " 3x + 2x " = 5x " .

→ The total number of students is represented as: " 5x " .
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→ The ratio of "girls to boys" is: "2x : 3x" .

→ {that is; the "inverse" of the ratio of "boys to girls"} ;
→ {that is; the "inverse" of " 3x: 2x" } ; → which is: " 2x : 3x " .
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The ratio of "girls" to "all students" is: "2x : 5x " ; or " 2x/5x " ;
→ Both "x" values cancel ; {since: " x/x = 1 "} ;
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→ and we have the answer: " 2 :5 " ; or, write as: " 2/5 " .
_________________________________________________________
The ratio of 'girls' to 'all students' is: " 2 :5 " ; or, write as: " 2/5 ".
_________________________________________________________

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3. Consider the expressions sq root of 15, sq root of 97 and sq root of 40 Locate the approximate value of each on a number line

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Answer:

Square root of 15

√ 15 = 3.9 (Rounding to the nearest tenth)

Square root of 97

√97 = 9.9 (Rounding to the nearest tenth)

Square root of 40

√40 = 6.3 (Rounding to the nearest tenth)

Step-by-step explanation:

Square root of 15

√ 15 = 3.9 (Rounding to the nearest tenth)

Square root of 97

√97 = 9.9 (Rounding to the nearest tenth)

Square root of 40

√40 = 6.3 (Rounding to the nearest tenth)

Location on a number line

√ 15, between + 3 and + 4, very close to +4

√40, between + 6 and + 7, close to +6

√97, between + 9 and + 10, very close to +10

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2 years ago

If sin∠E = cos∠F and m∠E = 43°, what is m∠F?

sukhopar [10]

Using complementary angles, it is found that F = 47º.

<h3>What are complementary angles?</h3>

Two angles are complementary if the sum of their measures is of 90º.

If two angles A and B are complementary, the sine of one angle is the cosine of the other.

In this problem, 43º and 47º are complementary, hence:

sin 43º = cos 47º, which means that F = 47º.

More can be learned about complementary angles at brainly.com/question/11161460

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2 years ago

Wrie down the equation of the line that is parallel to 4x - 2y = 7 and passes through (9, -3)

EastWind [94]

Answer:

4x-2y =42 is the required equation

Step-by-step explanation:

given equation is,

4x-2y -7=0---------eqn1

parallel equation of given equation is

4x -2y+k =0-------eqn 2

now passing it through (9,-3), we get,

4×9 + 2×3 +k = 0

or,36+6+k =0

or,42+k =0

or, k= -42

putting the value of k in eqn2

4x-2y - 42=0

4x-2y = 42

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3 years ago

The National Honor Society at Central High School plans to sample a random group

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Answer:A

Step-by-step explanation:

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3 years ago

Read 2 more answers

The length of a rectangle is 3 1/6 cm longer than the width. The perimeter of the rectangle is 15 1/3 cm. What are the width and

timofeeve [1]

Answer:

$Width = 2\frac{1}{4}cm$

$Length=5\frac{5}{12} cm$

Step-by-step explanation:

Data from the question;

Perimeter of a rectangle is $15\frac{1}{3}$ cm

Length is $3\frac{1}{6}$ cm longer than the width

We are supposed to determine the length and the with of the rectangle;

Assuming, the width x cm

Then, the length is $x+3\frac{1}{6}$ cm

We need to know that the perimeter of a rectangle is given by;

Perimeter = 2 ( length + width)

Therefore;

$15\frac{1}{3}= 2 ( x + (x+3\frac{1}{6}))$

$15\frac{1}{3}=2(2x+3\frac{1}{6})$

Thus;

$15\frac{1}{3}=4x+6\frac{1}{3}$

$4x=9\\x=2\frac{1}{4}$

Therefore;

$Width = 2\frac{1}{4}cm$

$Length = x + 3\frac{1}{6}$

$=2\frac{1}{4}+3\frac{1}{6}$

$=5\frac{5}{12} cm$

Therefore; the length is $5\frac{5}{12}$ cm while the width is $2\frac{1}{4}$ cm

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3 years ago