Answer:
2H2S (g) + 3O2 (g) → 2H2O (l) + 2SO2 (g)
Calculate ΔH° from the given data. Is the reaction exothermic or endothermic?
ΔH°f (H2S) = -20.15 kJ/mol; ΔH°f (O2) = 0 kJ/, mol; ΔH°f (H2O) = -285.8 kJ/mol; ΔH°f (SO2) = -296.4 kJ/mol
Answer:
y=2x-2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(8-4)/(5-3)
m=4/2
m=2
y-y1=m(x-x1)
y-4=2(x-3)
y=2x-6+4
y=2x-2
Answer:
100 lol
Step-by-step explanation:
ty for the points! <3
Answer:2
Step-by-step explanation: