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Nata [24]
2 years ago
7

1.Un cazador ubicado en la coordenada C (-5,8) y un venado ubicado en las coordenadas V (7,1). Escala 1 unidad = 10 ma)Determina

los metros de separación entre el cazador y el venado en línea recta.
Mathematics
1 answer:
True [87]2 years ago
5 0

The distance between the coordinates in meters is 138.92m

Using the distance formula to calculate the distance between the coordinates as shown:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\

Given the coordinate points C(-5, 8) and V (7, 1)

Substitute the given coordinates into the formula

D = \sqrt{(7+5)^2+(1-8)^2} \\D = \sqrt{(12)^2+(-7)^2} \\D = \sqrt{144+49} \\D = \sqrt{193} \\D=13.892 units

Given that 1 unit = 10metres

D = 13.892 * 10

D = 138.92 meters

Hence the distance between the coordinates in meters is 138.92m

Learn more here: brainly.com/question/7245260

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The ratio of the radii of two circles is 2:3. The diameter of the smaller circle is 15 mm. What is the length of the diameter of
mixer [17]
The answer is 11.25 mm.

A diameter of a circle is twice of its radius: d = 2r    ⇒ r = d/2

small circle                                       large circle
radius: r1                                           radius: r2 = ?
diameter: d1 = 15 mm
⇒ r1 = d1/2 = 15/2 mm

Since t<span>he ratio of the radii of two circles is 2:3, we have:
r1 : r2 = 2 : 3
which can also be expressed as:
</span>\frac{r1}{r2}= \frac{2}{3}
<span>
We know that r1 is 7.5, so let's implement it:
</span>\frac{7.5}{r2} = \frac{2}{3}

Let's multiply both sides of the by 3r2:
3r2* \frac{7.5}{r2} =3r2* \frac{2}{3}
⇒ 3 * 7.5 = 2*r2
     22.5 = 2*r2
⇒ r2= \frac{22.5}{2} =11.25 mm

5 0
3 years ago
Read 2 more answers
The product of five and a number plus 10 is at least thirty
inna [77]

Answer: Greater of equal sign

Step-by-step explanation:

5+10+x is greater than or equal to 30 ( use the greater of equal to sign)

7 0
2 years ago
Blank a function is the same as moving a function
earnstyle [38]

Answer:

Shifting/Translating the function

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Dont even know where to start
zalisa [80]

Answer:

\displaystyle M =  ( 3,1 )

Step-by-step explanation:

we are given the endpoint i.e P and Q of a line segment

we want to figure out the Midpoint of the Line segment

in order to do so we can use Midpoint formula given by

\displaystyle M =  \bigg( \frac{ x_{1} +  x_{2}  }{2}  , \frac{ y_{1} +  y_{2}}{2}  \bigg)

so let

x_1=-2\\x_2=8\\y_1=-2\\y_2=4

substitute

\displaystyle M =  \bigg( \frac{  - 2 +  8}{2}  , \frac{  - 2 +  4}{2}  \bigg)

simplify addition:

\displaystyle M =  \bigg( \frac{  6}{2}  , \frac{  2}{2}  \bigg)

simplify division:

\displaystyle M =  ( 3,1 )

hence,

the Midpoint of the line segment is (3,1)

5 0
3 years ago
List all possible rational roots. Then use synthetic division to confirm which rational roots exist:
Kisachek [45]

Answer:

\boxed{(1) \, x = \, \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10; (2) \, x = -2}

Step-by-step explanation:

2x³+ 6x² - x - 10 = 0

(1) Possible roots

The Rational Roots Theorem states that, if a polynomial has any rational roots, they will have the form p/q, where p is a factor of the constant term  and q is a factor of the leading coefficient.

\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}

In your function, the constant term is -10 and the leading coefficient is 2, so

\text{Possible root} = \dfrac{\text{factor of 10}}{\text{factor of 2}}

Factors of 10 = ±1, ±2, ±5, ±10

Factors of 2 = ±1, ±2

\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}

(2) Synthetic division

Rather than work through all 12 possibilities, I will do one that works.

\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}

So, x = -2 is a root, and the quotient is 2x² + 2x - 5.

(3) Check for other rational roots

2x² + 2x - 5 = 0

D = b² - 4ac =2²- 4(2)(-5) = 4 + 40 = 44

√44 = 2√11, which is irrational.

Since irrational roots come in pairs, the cubic equation has two real, irrational roots and one rational root at x = -2.

6 0
3 years ago
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