Question

1.Un cazador ubicado en la coordenada C (-5,8) y un venado ubicado en las coordenadas V (7,1). Escala 1 unidad = 10 ma)Determina los metros de separación entre el cazador y el venado en línea recta.

Answer 1

The distance between the coordinates in meters is 138.92m

Using the distance formula to calculate the distance between the coordinates as shown:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given the coordinate points C(-5, 8) and V (7, 1)

Substitute the given coordinates into the formula

$D = \sqrt{(7+5)^2+(1-8)^2} \\D = \sqrt{(12)^2+(-7)^2} \\D = \sqrt{144+49} \\D = \sqrt{193} \\D=13.892 units$

Given that 1 unit = 10metres

D = 13.892 * 10

D = 138.92 meters

Hence the distance between the coordinates in meters is 138.92m

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