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3 years ago

What is bigger 1/3 or 3/5

Mathematics

1 answer:

raketka [301]3 years ago

6 0

$Method\ 1:$

$\dfrac{1}{3}=\dfrac{1\cdot5}{3\cdot5}=\dfrac{5}{15}\\\\\dfrac{3}{5}=\dfrac{3\cdot3}{5\cdot3}=\dfrac{9}{15}\\\\\dfrac{3}{15} < \dfrac{9}{15}\ therefore\ \dfrac{3}{5}\ is\ bigger$

$Method\ 2:$

$\dfrac{1}{3} < \dfrac{1}{2}=\dfrac{1.5}{3}\\\\\dfrac{3}{5} > \dfrac{1}{2}=\dfrac{2.5}{5}\\\\therefore\ \dfrac{3}{5}\ is\ bigger$

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2 years ago

Chin made an error in his chart showing the multiplication of the binomial by the trinomial. Which change can be made to correct

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The expression 6x should be 6x^2.

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A bag contains 10 red marbles and 15 green marbles.If yuki selects a marble from the bag without looking, what is the probabilit

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Incomplete Question (See Complete Question Below)

A bag contains 10 red marbles and 15 green marbles.If Yuki selects a marble from the bag without looking, what is the probability that she will pull a red marble?

A-1/5

B-2/5

C-1/2

Answer:

The probability of pulling a red marble is $\frac{2}{5}$

Step-by-step explanation:

Given

Red Marble = 10

Green Marble = 15

Required

The probability of picking a red marble

First, the total number of marble has to be calculated

Total = Red Marble + Green Marble

Total = 10 marbles + 15 marbles

Total = 25 marbles

The probability of an event is often calculated by dividing the number of required outcomes by the number of possible outcomes.

In this case, the probability of pulling a red marble is calculated as follows:

$P(R) = \frac{n(R)}{T}$

Where P(R) represents probability of pulling a red marble

n(R) represents number of red marbles

n(R) = 10

T represents total number of marbles

T = 25

By substitution,

$P(R) = \frac{n(R)}{T}$ becomes

$P(R) = \frac{10}{25}$

Reduce fraction to lowest term by dividing the numerator and denominator by 5

$P(R) = \frac{2}{5}$

Hence, the probability of pulling a red marble is $\frac{2}{5}$

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