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Neko [114]
3 years ago
7

Seven ping-pong balls numbered 1-7 are put in a hat. Three balls are chosen without replacement. What is the probability that al

l three numbers are even numbers?
Mathematics
2 answers:
muminat3 years ago
5 0
Probability of 1st number being even : 3/7
probability of 2nd number being even : 2/6
probability of 3rd number being even : 1/5

probability of all 3 numbers being even : 3/7 * 2/6 * 1/5 = 6/210 = 1/35
Nat2105 [25]3 years ago
4 0
<h2>Answer:</h2>

The probability that all three numbers are even numbers is:

             \dfrac{1}{35}

<h2>Step-by-step explanation:</h2>

There are seven balls numbered as: 1-7

and the number of even numbers are: 3  ( i.e. 2,4 and 6 )

Three balls are chosen without replacement.

Hence, the probability that all three numbers are even numbers is given by:

 Ratio of number of favorable outcomes to the total number of outcomes.

Hence, the probability is:

P(All\ three\ even\ numbers)=\dfrac{3_C_3}{7_C_3}

where the numerator represents that the balls drawn have  even numbers.

and the denominator denote the choosing of 3 balls out of a total of 7 balls.

Hence, the probability is:

P(All\ three\ even\ numbers)=\dfrac{1}{35}

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