The data shows tha ages of teachers at a school. You may draw a box plot to help you. 33, 25, 42, 25, 31, 37, 43, 29, 38, 25, 25
AnnyKZ [126]
Answer:
Median: 33
Third Quartile: 39
Interquartile Range:
Step-by-step explanation:
25 25 25 25 29 29 31 31 33 33 37 37 38 38 42 42 43 43
The median is the middle, so the median is 33 (there's two but both are 33 so that averages to 33)
Third Quartile: I don't know how to explain it I forgot how to do this since I did it last year (I used the internet oops)
Interquartile Range: 11
Answer:
7.5
Step-by-step explanation:
<u>To find the median, first order the numbers from least to greatest:</u>
2, 4, 5, 7, 8, 8, 10, 12
<u>Then, find the middle number (number in the middle):</u>
There are 2 middle numbers. 7 and 8.
Because there are 2 numbers, we need to find the average. If there was only one number, that would be the median.
<u>To find the average, add 7 and 8. Then, divide the sum by 2 because there are 2 numbers;</u>
7 + 8 = 15
15 / 2 = 7.5
Have a nice day!
Rhombus , 4 sides are equal
so
AB = √(15^2 +20^2)
AB = √(225 + 400)
AB = √625
AB = 25
P = 4a
P = 4(25)
P = 100
answer
H. 100 in
It's number C, because if you get the sum of the expressions you get the perimeter of 9a + 4b - 5.
X + 7 + 4x + 3 = 180
5x + 10 = 180
5x = 170
x = 34