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aalyn [17]
3 years ago
15

HELP PLEASE I NEED IT NOWWW.

Mathematics
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

C.) 5

Step-by-step explanation:

If beth were 5 ( Making Julio 3)

Gerald is 10 and Debra is 20

10+20+5+3 = 38

I hope this helps you :)

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What is the sum of 62/100
andrey2020 [161]
If you were to add these both you would get 162 

62+100=162
3 0
3 years ago
a bus is leaving the bus station at 5:45 p.m. and it takes 2 days 6 hours 30 minutes to reach a destination if the bus leaves on
Fudgin [204]

Answer:

Monday, at 12:15 AM

Step-by-step explanation:

Do this question in parts. First, add 2 days to Friday to get Sunday at 5:45 PM. Then, add 6 hours to 5:45 to get 11:45 PM. Finally, add 30 minutes to 11:45 PM. That takes you to 12:15, and since you passed midnight, Sunday is now Monday. That means the bus arrives Monday, at 12:15 AM.

8 0
3 years ago
Can someone please help me!!!!!
Aneli [31]
The coordinates of the point of intersection are read from the graph as ...
  (3, 5).
4 0
3 years ago
If cos (A) = 1/2 with A in QIV, find sec (A/2).
Ludmilka [50]
If A is QIV, then        3π/2 ≤A≤2π; 
we have to find out in what quadrant is A/2
          (3π/2)/2≤A/2≤(2π)/2 ⇒ 3π/4≤A/2≤π
We can see that A/2 will be in QIII; therefore the sec (A/2) will be negative (-).

1) we have to calculate cos (A/2)
Cos (A/2)=⁺₋√[(1+cos A/2)/2]
We choose this formula: Cos (A/2)= -√[(1+cos A/2)/2],  because sec A/2 is in quadrant Q III, and the secant (sec A/2=1/cos A/2) in this quadrant is negative.

Cos (A/2)=-√[(1+cos A)/2]=-√[(1+(1/2)]/2=-√(3/4)=-(√3)/2.

2) we compute the sec (A/2)
Data:
cos (A/2)=-(√3)/2

sec (A/2)=1/cos (A/2)
sec (A/2)=1/(-(√3)/2)=-2/√3=-(2√3)/3

Answer: sec (A/2)=-(2√3)/3
6 0
4 years ago
Simplify 4(6 - 2x) - 3(3 - 4x)<br><br> 4x + 15<br> 15 - 20x<br> 15 - 6x
Whitepunk [10]
First use distributive property:
4(6 - 2x) - 3(3 - 4x)
24 - 8x - 9 + 12x
Add like terms:
4x + 15
4 0
3 years ago
Read 2 more answers
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