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vovikov84 [41]
2 years ago
9

GOD BELIEVES YOU CAN HELP ME

Mathematics
2 answers:
Paladinen [302]2 years ago
8 0

Answer:

40%

You are welcome <33

Step-by-step explanation:

12345 [234]2 years ago
3 0

Answer:

40 percent

2/5 is 40 percent

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PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!! I NEED TO FINISH THESE QUESTIONS BEFORE MIDNIGHT TONIGHT.
Natali [406]

Yo sup??

To solve this question we have to apply trigonometric ratios

sin31=UT/TV

TV=UT/sin31

=7.76

=7.8

Hope this helps.

6 0
3 years ago
The height h of a projectile is a function of the time t it is in the air. the height in feet for t seconds is given by the func
alexgriva [62]

Domain means the values of independent variable(input) which will give defined output to the function.

Given:

The height h of a projectile is a function of the time t it is in the air. The height in feet for t seconds is given by the function

h(t)=-16t^2 + 96t

Solution:

To get defined output, the height h(t) need to be greater than or equal to zero. We need to set up an inequality and solve it to find the domain values.

To \; find \; domain:\\\\h(t) \geq0\\\\-16t^2+96t \geq  0\\Factoring \; -16t \; in \; the \; left \; side \; of \; the \; inequality\\\\-16t(t-6) \geq  0\\Step \; 1: Find \; Boundary \; Points \; by \; setting \; up \; above \; inequality \; to \; zero.\\\\t(t-6)=0\\Use \; zero \; factor \; property \; to \; solve\\\\t=0 \; (or) \; t = 6\\\\Step \; 2: \; List \; the \; possible  \; solution \; interval \; using \; boundary \; points\\(- \infty,0], \; [0, 6], \& [6, \infty)

Step \; 3:Pick \; test \; point \; from \; each \; interval \; to \; check \; whether \\\; makes \; the \; inequality \; TRUE \; or \; FALSE\\\\When \; t = -1\\-16(-1)(-1-6) \geq  0\\-112 \geq  0 \; FALSE\\(-\infty, 0] \; is \; not \; solution\\Also \; Logically \; time \; t \; cannot \; be \; negative\\\\When \; t = 1\\-16(1)(1-6) \geq  0\\80 \geq  0 \; TRUE\\ \; [0, 6] \; is \; a \; solution\\\\When \; t = 7\\-16(7)(7-6) \geq  0\\-112 \geq  0 \; FALSE\\ \; [6, -\infty) \; is \; not \; solution

Conclusion:

The domain of the function is the time in between 0 to 6 seconds

0 \leq  t \leq  6

The height will be positive in the above interval.

7 0
3 years ago
Read 2 more answers
The radius of the tires of a car is 18 inches, and they are revolving at the rate of 651 revolutions per minute. How fast is the
Mumz [18]
So the car is moving at 651 revolutions per minute, with wheels of a radius of 18inches

so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"

now, what's the linear velocity, namely, the arc covered per minute

well   \bf v=rw\qquad &#10;\begin{cases}&#10;v=\textit{linear velocity}\\&#10;r=radius\\&#10;w=\textit{angular velocity}\\&#10;----------\\&#10;r=18in\\&#10;w=1302\frac{\pi }{min}&#10;\end{cases}\implies v=18in\cdot \cfrac{1302\pi }{min}&#10;\\\\\\&#10;v=\cfrac{23436\pi\ in}{min}

now, how much is that in miles/hrs?  well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr

thus   \bf \cfrac{23436\pi\ in}{min}\cdot \cfrac{ft}{12in}\cdot \cfrac{mi}{5280ft}\cdot \cfrac{60min}{hr}\implies \cfrac{23436\cdot \pi \cdot 60\ mi}{12\cdot 5280\ hr}

notice, after all the units cancellations, you're only left with mi/hrs
4 0
3 years ago
Help please been stuck on this for a week.
Anettt [7]
They give the formula as:
Surface Area =<span> (2 • <span>π <span>• r²) + (2 • <span>π • r • height)</span></span></span></span>
However the 2*PI*r^2 part of the formula is used to calculate the 2 "ends" of a cylinder.  Since the problem states that you are NOT to count any of surface area of the "ends" then you only need the <span>(2 • <span>π • r • height) part of the formula.
So, r = 3 inches and height = 8 * 3 inches, the side area equals
2 * PI * r * height
2 * 3.14159 * 3 * 24 =
</span></span>
<span> <span> <span> 452.39 cubic inches which is the lateral area.</span></span></span>



6 0
3 years ago
Use the compound interest formulas A= P (1 + r/n) ^nt and A= Pe ^ rt to solve the problem given. Round to the nearest cent. Find
Dennis_Churaev [7]

Answer:

  1. \$30,460
  2. \$30,497
  3. \$30,522
  4. \$30,535

Step-by-step explanation:

We know that,

A=P\left (1+\dfrac{r}{n}\right )^{n\cdot t}

where,

A = Amount after time t,

P = Principle amount,

r = Rate of interest,

n = Number of times interest is compounded per year,

t = time period in year.

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded semiannually

Here,

P = $25,000

r = 5% = 0.05

n = 2 (as compounded semiannually)

t = 4 years

Putting the values,

A=25000\left (1+\dfrac{0.05}{2}\right )^{2\times 4}

=25000\left (1+0.025\right )^{8}

=25000\left (1.025\right )^{8}

=\$30,460

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded quarterly.

Here,

P = $25,000

r = 5% = 0.05

n = 4 (as compounded quarterly)

t = 4 years

Putting the values,

A=25000\left (1+\dfrac{0.05}{4}\right )^{4\times 4}

=25000\left (1+0.0125\right )^{16}

=25000\left (1.0125\right )^{8}

=\$30,497

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded monthly.

Here,

P = $25,000

r = 5% = 0.05

n = 12 (as compounded monthly)

t = 4 years

Putting the values,

A=25000\left (1+\dfrac{0.05}{12}\right )^{12\times 4}

A=25000\left (1+\dfrac{0.05}{12}\right )^{48}

=\$30,522

Investment of $25,000 for 4 years at an interest rate of 5% if the money is compounded continuously.

A= Pe^{rt}

where,

A = Amount after time t,

P = Principle amount,

r = Rate of interest,

t = time period in year.

Putting all the values,

A= 25000e^{0.05\times 4}=\$30,535

It can be observed that, the frequent we compound the amount, the more we get.

7 0
3 years ago
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