Answer:
the environment and parasites
Urine Specimen must be chilled if testing will not be performed immediately.
<h3>What is Urine?</h3>
Urine is a liquid byproduct of human and many other animal metabolism. Urine travels from the kidneys to the urinary bladder via the ureters. Urine is discharged from the body through the urethra as a result of urination.
Many by-products of cellular metabolism, such as urea, uric acid, and creatinine, are nitrogen-rich and must be removed from the bloodstream. These by-products are excreted from the body through urination, which is the major way for excreting water-soluble compounds. A urinalysis can identify nitrogenous wastes in mammals.
To learn more about urine visit:
brainly.com/question/27454851
#SPJ4
Question:
<em>The diagram shows the potential energy changes for a reaction pathway.</em>
Part 1: Does the diagram illustrate an endothermic or an exothermic reaction? Give reasons in support of your answer.
Part 2: Describe how you can determine the total change in enthalpy and activation energy from the diagram and if each is positive or negative.
Answer:
Part 1: The diagram illustrates an endothermic reaction as the products has a higher potential energy than the reactants do. There is a positive slope of the diagram and there is enough energy to meet the activation energy requirement.
Part 2: You can determine the total change in enthalpy and activation energy from the diagram by the potential energy of the reactants. If the reactants have a high potential energy, then the enthalpy is also high, and if the reactants have a low potential energy, then the enthalpy is low. You can determine if the diagram is positive or negative by knowing if its an endothermic or exothermic reaction. An endothermic reaction is positive because the products are higher than the reactants and a exothermic reaction is negative because the reactants are higher than the products.
Answer:
Yes possible
Explanation:
If mother is heterozygous A then her alleles are iA and iO while father is AB so crossing the two we get AO, AA, AB and BO. Hence proved