I would say the answer is 2
Answer:
Terms must have the same variable (letter) and the same exponent (little number)
(7x² +3y+ 5) +(9x²+11y- 2)
Opening bracket
7x²+3y+5+9x²+11y-2
keeping like terms together
7x²+9x²+3y+11y+5-2
Since terms having same variable and exponent can be subtracted, added,divided and multiplied
So
Solving like terms we get
<u>16x²+14y+3</u> which is a correct answer.
X is radical 3
y is 2 radical 3
The given options are:
- (A)x+y = 20
- (B)7 apps and 14 movies
- (C)x-y= 20
- (D)y=-x+ 20
- (E)8 apps and 12 movies
- (F)xy= 20
Answer:
- (A)x+y = 20
- (D)y=-x+ 20
- (E)8 apps and 12 movies
Step-by-step explanation:
If Elizabeth has a combined total of 20 apps and movies.
Where:
Number of apps=x
Number of Movies =y
Then:
Their total,
If we subtract x from both sides
x+y-x=-x+20
In Option E
8 apps and 12 movies add up to 20. Therefore, this could also apply.
Answer:
4 . The answer is no .
5 . x=1
6. unlimited answers
7. There's no answer to this question .
Step-by-step explanation:
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4. solution :
-20(2-4) = 2((5×-4) -4) =
-40 = -48 × impossible
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5. solution :
-3+4x+12x+24 = 28x +12-3
-3+24-12+3=28x-12x-4x
27-15=12 = 2x - 16x =12x
12 = 12x
x =1
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6. solution :
24-3x+9-6 = -8x+20+5x+7
8x-5x-3x = -24-9+6+20+7
0=0
x can be every number you think because they are always equal to each other .
examination :
if you consider x as 1 :
24-3+9-6=-8+20+5+7
24=24
or if you consider x as 2 :
24-6+9-6 = -16+20+10+7
21 = 21
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7 . solution :
3(x-2) = 3x+4
3x-6 = 3x+4
3x-3x = 10
0 = 10
if you consider x as 1 :
3-6 = 3+4
-3 = 7 × impossible .
