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melamori03 [73]
3 years ago
5

At a factory that produces pistons for cars, Machine 1 produced 174 satisfactory pistons and 116 unsatisfactory pistons today. M

achine 2 produced 180 satisfactory pistons and 20 unsatisfactory pistons today. Suppose that one piston from Machine 1 and one piston from Machine 2 are chosen at random from today's batch. What is the probability that the piston chosen from Machine 1 is satisfactory and the piston chosen from Machine 2 is unsatisfactory
Mathematics
1 answer:
m_a_m_a [10]3 years ago
5 0

Answer:

0.7 is the probability that the piston chosen from Machine 1 is satisfactory and the piston chosen from Machine 2 is unsatisfactory

Step-by-step explanation:

The two events are independent of each other.

Hence the probability of choosing satisfactory piston from Machine 1 and unsatisfactory piston from Machine 2 is equal  probability of choosing satisfactory piston from Machine 1 + probability of choosing unsatisfactory piston from Machine 2

Substituting the given values we get

Probability of choosing satisfactory piston from Machine 1 and unsatisfactory piston from Machine 2 =\frac{174}{174 +116} + \frac{20}{180 +20}

=\frac{174}{174 +116} + \frac{20}{180 +20}

== \frac{174}{290} + \frac{20}{200}\\= 0.6 + 0.1\\= 0.7

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