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Grace [21]
3 years ago
14

5(4x-1)-2x=31 what does x equal

Mathematics
2 answers:
Elenna [48]3 years ago
6 0

Answer:

X=2

Step-by-step explanation:

5(4x-1)-2x=31

Distribute the 5

20x-5-2x=31

18x-5=31

18x=31+5

18x=36

When you divide you get 2

Also, Photomath exists, it’s great for math problems

ehidna [41]3 years ago
3 0

20x - 5 - 2x = 31

18x = 36

x = 2

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Pls help me with either one
blagie [28]

7. 65 + 75 = 140

180 - 140 = 40

( I think this is the answer)

6 0
3 years ago
Read 2 more answers
Need answer asap!!!!!<br><br> how would i solve this?
lesya [120]

The height of the building to the nearest tenth of a meter is; 13 m

<h3>How to make use of Cosine Rule?</h3>

The slant line from the top of Trevor's head to the base of the building is gotten from Pythagoras theorem;

15/x = sin 36°

x = 15/sin 36

x = 25.52 m

Angle between that slant line and base of building is;

90 - tan⁻¹(1.5/14) = θ

θ = 83.88°

Remaining angle of the bigger triangle is;

180 - (36 + 83.88) = 60.12°

Thus, if the height of the building is h, then;

h/sin 36 = 25.52/sin 60.12

h = 13 m

Read more about Cosine Rule at; brainly.com/question/4372174

#SPJ1

5 0
2 years ago
Pls can anyone give me tips for studying when I'm high-school ​
dimulka [17.4K]

Answer:

take a break from social media , find a peaceful spot to study ,be engaged , take notes and listen during discussion make use of ur extra time wisely

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5 0
3 years ago
Integrate the following
enot [183]

I suppose you mean to have the entire numerator under the square root?

\displaystyle\int_2^4\frac{\sqrt{x^2-4}}{x^2}\,\mathrm dx

We can use a trigonometric substitution to start:

x=2\sec t\implies\mathrm dx=2\sec t\tan t\,\mathrm dt

Then for x=2, t=\sec^{-1}1=0; for x=4, t=\sec^{-1}2=\frac\pi3. So the integral is equivalent to

\displaystyle\int_0^{\pi/3}\frac{\sqrt{(2\sec t)^2-4}}{(2\sec t)^2}(2\sec t\tan t)\,\mathrm dt=\int_0^{\pi/3}\frac{\tan^2t}{\sec t}\,\mathrm dt

We can write

\dfrac{\tan^2t}{\sec t}=\dfrac{\frac{\sin^2t}{\cos^2t}}{\frac1{\cos t}}=\dfrac{\sin^2t}{\cos t}=\dfrac{1-\cos^2t}{\cos t}=\sec t-\cos t

so the integral becomes

\displaystyle\int_0^{\pi/3}(\sec t-\cos t)\,\mathrm dt=\boxed{\ln(2+\sqrt3)-\frac{\sqrt3}2}

7 0
3 years ago
Which is greater .75 or 7/8
soldier1979 [14.2K]

Answer:

.75 < 7/8

Step-by-step explanation:

Lets change the decimal to a fraction

.75 = 75/100

Divide the top and bottom by 25

75/100 = 3/4

Multiply by 2/2

3/4*2/2 = 6/8

6/8 < 7/8

so .75 < 7/8

5 0
3 years ago
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