A mother who is 40 years old has a daughter and a son. The son is twice as old as the daughter. In 15 years the sum of all their ages will be 100 years. How old are the siblings now?
2 answers:
Answer:
15 and 5
Step-by-step explanation:
Mother's current age: 40
daughter's age: d
son's age: s
son is 2x as old as daughter: s = 2d
Then, 15 years from now, the sum of their ages will be:
(40 + 15) + (2d + 15) + (d + 15) = 100
or
55 + 15 + 15 + 3d = 100
85 + 3d = 100, or 3d = 15, or d = 5.
Then the son's age is 3(5) = 15 and the daughter's is 5.
Answer:
the son is 30 and the daughter is 15
Step-by-step explanation:
the mom is 55 in 15 years
100-55=45
45-30=15
15x2=30
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