The set of all possibilities is called sample space and is denoted by S.
So, S = {NBD, NDB, BDN, BND, DBN, DNB} and n(S) = 8
and we need to find the probability of NBD
E = {NBD} and n(E) = 1
The probability of an even is defined by p(E) = 
Hence, p(E) = 
Answer:
Step-by-step explanation:
The union of two sets is a new set that contains all of the elements that are in at least one of the two sets. The union is written as A∪B or “A or B”. The intersection of two sets is a new set that contains all of the elements that are in both sets. The intersection is written as A∩B or “A and B”.
Hope this helps ^^
Answer:
c4+8c3+−3c2+−7c
Step-by-step explanation:
Let's simplify step-by-step.
−3c4−5c2−7c+4c4+8c3+2c2
=−3c4+−5c2+−7c+4c4+8c3+2c2
Combine Like Terms:
=−3c4+−5c2+−7c+4c4+8c3+2c2
=(−3c4+4c4)+(8c3)+(−5c2+2c2)+(−7c)
=c4+8c3+−3c2+−7c